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Alex Ar [27]
3 years ago
7

Find the slope of the line that passes through A(0,−5) and B(3,−4) .

Mathematics
1 answer:
Brut [27]3 years ago
8 0

Answer: 1/3

Step-by-step explanation: slope is the difference between the y values over the difference of the x values

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If you can help with any of these two or both that would be great ! :) <br> thanks
Vladimir [108]

Answer:

hmmm not sure

Step-by-step explanation:

try mulitply the numbers

7 0
3 years ago
Multiply using FOIL or Table method (x + 4) (x + 5)
mylen [45]

Answer:

{x}^{2}  + 9x + 20

Step-by-step explanation:

1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

{x}^{2}  + 5x + 4x + 20

2) Collect like terms.

{x}^{2}  + (5x + 4x) + 20

3) Simplify.

{x}^{2}  + 9x + 20

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>9x</u><u> </u><u>+</u><u> </u><u>20</u>.

5 0
3 years ago
The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice
777dan777 [17]
If period of f(\theta) is one-half the period of g(\theta) and
<span>g(\theta)  has a period of 2π, then T_{g} =2T_{f}=2 \pi and T_{f}= \pi.
</span>
To find the period of sine function f(\theta)=asin(b\theta+c) we use the rule T_{f}= \frac{2\pi}{b}.
<span /><span />
f is sine function where f (0)=0, then c=0; with period \pi, then f(\theta)=asin 2\theta, because T_{f}= \frac{2 \pi }{2} = \pi. 

To find a we consider the condition f( \frac{ \pi }{4} )=4, from where asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4.

If the amplitude of f(\theta) is twice the amplitude of g(\theta) , then g(\theta) has a product factor twice smaller than f(\theta) and while period of g(\theta)<span> </span> is 2π and g(0)=0, we can write g(\theta)=2sin\theta.






8 0
3 years ago
Milly has 636 shopkins arranged in 12 rows how many shopkins are in each row
kodGreya [7K]
Divide 636 / 12 which equals 53 ?
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