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likoan [24]
3 years ago
7

1. What is one of the important roles of tropical rainforests in the earth's environment?

Chemistry
1 answer:
Makovka662 [10]3 years ago
3 0

Answer:

1.D

2.C

3.D

4.D

5.C

6 B

those are the answers, we must take care of our environment

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A common laboratory method for preparing a precipitate is to mix solutions containing the component ions. Does a precipitate for
laiz [17]

Answer:

CaF2 will not precipitate

Explanation:

Given

Volume of Ca(NO3)2 = 10 ml

Molar concentration of Ca(NO3)2 = 0.001

Volume of NaF = 10 ml

Molar concentration of  NaF  = 0.0001

Ksp for CaF2 = 3.2 * 10^ {-11}

CaF2 will precipitate if Q for the reaction is greater than ksp of CAF2

Moles of calcium ion

= 10 * 0.001\\= 0.01

[Ca2+] = \frac{0.01}{10 + 10} \\= \frac{0.01}{20} \\= 5 * 10^{-4}

Moles of F- ion

= 10 * 0.0001\\= 0.001

[F-] = \frac{0.001}{10 + 10} \\= \frac{0.001}{20} \\= 5 * 10^{-5}

Q = [Ca2+] [F-]^2\\= (5 * 10^{-4}) * (0.5* 10^-4)\\= 1.25 * 10^{-12}

Q is lesser than Ksp value of CaF2. Hence it will not precipitate

5 0
3 years ago
The reaction PCl3(g)+Cl2(g)???PCl5(g)
goldfiish [28.3K]

Answer:

Just study the thing don't expect others to just answer the homework for you

Explanation:

If you truly are a good student then you should have asked your teacher in person or through email instead of asking on here. Not trying to be mean but you also have to understand that people on here have a life. :)

5 0
3 years ago
Read 2 more answers
Look at the atom models you made in today’s activities. Name the three parts of the atom. A. protons, neutrons, and electrons B.
Musya8 [376]
D, protons,molecules, and electrons
5 0
3 years ago
Analyze the following blood splatter pictures to determine the general direction, origin, and impact
kkurt [141]

Answer:

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3 0
3 years ago
Consider a 1260-kg automobile clocked by law-enforcement radar at a speed of 85.5 km/h. If the position of the car is known to w
-BARSIC- [3]
The expected speed is v = 85.5 km/h
 v = 85.5 km/h = (85.5 km/h)*(0.2778 (m/s)/(km/h)) = 23.75 m/s

If there is an uncertainty of 2 meters in measuring the position, then within a 1-second time interval:
The lower measurement for the speed is v₁ = 21.75 m/s,
The upper measurement for the speed is v₂ = 25.75 m/s.
The range of variation is
Δv = v₂ - v₁ = 4 m/s

The uncertainty in measuring the speed is
Δv/v = 4/23.75 = 0.1684 = 16.84%

Answer: 16.8%
3 0
3 years ago
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