Im working on science too!! I would help you but the attachment isn't pulling up..
Answer:
Explanation:
Ag₂CO₃(s) ⇌2Ag⁺(aq) + CO₃²⁻(aq); Ksp = 8.10 × 10⁻¹²
2x 0.007 50 + x
Answer:
a H2CO3 b HCO3- and c H+ and HCO3-
Explanation:
As the pKa value of phenol is more than that of carbonic acid(H2CO3), the carbonic acid will have high Ka value than that of phenol.
The acid that contain high Ka value act as stong acid.From that point of view H2CO3 is a strong acid than phenol as the Ka value of carbonic acid is greater than that of phenol.
The conjugate base of H2CO3 is bicarbonate ion(HCO3-)
c The species that predorminates at equilibrium are H+ and HCO3-
Answer:
What type of bonds are shown in this diagram?
A: covalent bonds
B: ionic bonds
C: hydrogen bonds
D: metallic bonds
(answer) metallic bonds
In what type of bonds do atoms join together because their opposite charges attract each other?
A: metallic bonds and covalent bonds
B: metallic bonds and ionic bonds
C: ionic bonds and covalent bonds
D: ionic bonds and hydrogen bonds
(answer) ionic bonds and hydrogen bonds
What types of bonds are shown in this diagram?
A: covalent bonds
B: ionic bonds
C: hydrogen bonds
D: metallic bonds
(answer) hydrogen bonds
Which statement best describes the types of bonds shown in the diagram?
A: an ionic bond; the hydrogen chloride molecule has an electrical charge
B: an ionic bond; a hydrogen ion is bonding with a chlorine atom
C: a covalent bond; the hydrogen atom’s two electrons are being shared with the chlorine atom
D: a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
(answer) a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
Which of the following bonds is the strongest?
A: hydrogen bonds
B: metallic bonds
C: valence bonds
D: covalent bonds
(answer)
Explanation:
UwU
<span>pm stands for picometer and picometers are units which can be used to measure really tiny distances. One picometer is equal to 10^{-12} meters. We know that one centimeter is equal to 10^{-2} m so there are 10^2 cm per meter.
We can change the distance d = 115 pm to units of centimeters.
d = (115 pm) x (10^{-12}m / pm) x (10^2 cm / m)
d = 115 x 10^{-10} cm = 1.15 x 10^{-8} cm
The distance in centimeters is 1.15 x 10^{-8} cm</span>