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vivado [14]
3 years ago
11

Biological oxidation-reduction reactions always involve:

Chemistry
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

b. transfer of electron(s).

Explanation:

An oxidation-reduction also called a redox reaction is a

chemical reaction in which electrons are transferred of between two species of reactants. It is a chemical reaction where the oxidation number of an atom, ion, or molecule, increases or decreases by losing or gaining electrons

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A solution is prepared from 8 grams of acetic acid (CH2CO2H) and 725 grams of water. What is the molarity of this solution?
Andrews [41]
Hello!

First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL

Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:

[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H}  }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }

[CH_3CO_2H]=0,1818 M

So, the concentration of acetic acid would be 0,1818 M

Have a nice day!
4 0
4 years ago
Read 2 more answers
Can anyone help me ASAP
harkovskaia [24]

Answer: Balance, multiply, find ratio

Explanation:

Balance the equation to be able to multiply correctly and accurately, multiply, and this will give you the molar ratio

5 0
3 years ago
In run 1, you mix 8.0 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 2.60 mL of the 0.040 M SnCl2 in 2 M HCl solu
Phantasy [73]

The concentration of [Sn⁺²] will be calculated by first calculating the moles of SnCl₂ added as these moles will give us the moles of [Sn⁺²] ion.

Moles of SnCl₂ = molarity X volume = 0.04 X 2.60 = 0.104 milli moles [as volume is in mL]

The moles of [Sn⁺² = 0.104 mmol

the total volume in solution = volume due to MO + volume due to SnCl₂ + volume due to HCl + volume due to NaCl

Total volume = 8+2.60+5.43+3.73= 19.76 mL

Concentration = moles / volume

concentration [Sn⁺²]  = 0.104mmol / 19.76 mL = 0.0053 mol / L

4 0
3 years ago
A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely
Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

P_{total}=P_{NO_{2}}+P_{NO}

we don't include N_{2}O_{3} because it decomposed completely.

Assuming  ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of N_{2}O_{3} is:

n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}

from the  reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of N_{2}O_{3}.

n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}

n_{NO}=\frac{P_{1}V}{RT_{1}}

The partial pressure of each gas is:

P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}

P_{NO}=\frac{n_{NO}*R*T_{2}}{V}

so total pressure is:

P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}

replacing the moles we get:

P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}

We know that T2=3*T1

replacing this value in the equation we get:

P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}

P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm

5 0
3 years ago
When the equation below is correctly balanced, what is the coefficient for Fe?
Sedbober [7]

Answer:

2Fe + 3Cl=2FeCl3 therefore the coefficent for Fe is 2.

Explanation:

7 0
3 years ago
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