1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marissa [1.9K]
3 years ago
8

g Calculate the theoretical yield (in grams) of your product if you start with 0.50 grams of E-stilbene. The molecular weight of

E-stilbene is 180.25 g/mol, and the molecular weight of the product is 340.058 g/mol. 0.5109 grams 0.9433 g 0.2342 g 0.6312 g
Chemistry
1 answer:
sattari [20]3 years ago
4 0

Answer:

0.9433g

Explanation:

Theoretical yield is defined as the mass produced assuming all reactant reacts producing the product.

Assuming the reaction is 1:1, we need to find the moles of E-stilbene (Reactant). If all reactant reacts, the moles of E-stilbene = Moles of product.

Using the molar mass of the product we can find the theoretical yield as follows:

<em>Moles E-stilbene:</em>

0.50g * (1mol/180.25g) = 0.00277 moles = Moles Product

<em>Mass Product = Theoretical yield:</em>

0.00277 moles * (340.058g/mol) = 0.9433g

You might be interested in
ether has a density of 0.736 g/cm^3 at 20 degrees C. what is the volume, in liters, of 225.0 grams of ether?
polet [3.4K]
D = m / V

0.736 = 225.0 / V

V = 225.0 / 0.736

V = 305.7 cm³
5 0
3 years ago
Help please I’ll give you brainless
Helen [10]
• Liquid at room temperature
•Gas at room temperature
• Argon has approximately the same solubility in water as oxygen and is 2.5 times more soluble in water than nitrogen. Argon is colorless, odorless, nonflammable and nontoxic as a solid, liquid or gas. Argon is chemically inert under most conditions and forms no confirmed stable compounds at room temperature.
5 0
3 years ago
What does this equation, 2 C(s) + O 2(g) ® 2 CO(g), tell us?
Zanzabum

Answer:

D. All of these.

Explanation:

For an equation to be balanced the number of atoms of each kind in the reactants and the products should be the same.

Then from this equation, CO  is a product.

Last, two carbon atoms undergo reaction with the oxygen molecule for complete reaction to occur. Each atom combines with one oxygen atom.

7 0
3 years ago
Read 2 more answers
A hypothetical covalent molecule, X–Y, has a dipole moment of 1.93 1.93 D and a bond length of 109 pm. 109 pm. Calculate the par
Gnesinka [82]

Answer:

q= 110.5 ke

Explanation:

Dipole moment is the product of the separation of the ends of a dipole and the magnitude of the charges.

μ = q * d

μ= Dipole moment (1.93 D)

q= partial charge on each pole

d= separation between the poles(109 pm).

e= electronic charge ( 1.60217662 × 10⁻¹⁹ coulombs)

So,

q= \frac{1.93}{109 * 10^{-12} } coulombs

q = \frac{1.93}{109 * 10^{-12} *  1.60217662 * 10^{-19} } e

q = 1.105 * 10⁵ e

q= 110.5 ke

4 0
3 years ago
What is the gravitational force between you and Earth?<br><br>A. Weight<br>B. Force​
damaskus [11]

Answer:

force

Explanation:

mark brainliest?

8 0
3 years ago
Other questions:
  • Which example best shows conservation of resources?
    5·2 answers
  • Which is classified as a pure substance?
    7·2 answers
  • Does lithium or potassium have a strong nuclear pull
    14·1 answer
  • Please help!!!!
    7·1 answer
  • An element has three stable isotopes with masses of 27.977 amu, 28.976 amu, and 29.973 amu. The heavier two isotopes have an abu
    7·1 answer
  • The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
    13·1 answer
  • I NEED HELP ASAP PLEASE I BEG
    8·1 answer
  • The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If
    9·1 answer
  • 2H20 → 2H2 + O2<br> Type of reaction?
    6·1 answer
  • Is the flow of energy during vaporizing more like the flow of energy during melting or during freezing?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!