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Tju [1.3M]
1 year ago
7

The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal:CO(g) + H₂O(g) ⇄

CO₂(g) + H₂(g)At a given temperature, Kp = 2.7. If 0.13 mol of CO, 0.56 mol of H₂O, 0.62 mol of CO₂, and 0.43 mol of H₂ are put in a 2.0-L flask, in which direction does the reaction proceed?
Chemistry
1 answer:
lilavasa [31]1 year ago
8 0

The reaction will proceed in the reverse direction in order to increase the concentrations of both CO and H2O and decrease that of CO2 and H2 until Q = K.

The reaction will proceed to the left

Step 1: The balanced equation

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

Step 2: Data given

Kp = 2.7

Number of moles of CO = 0.13 mol

Number of moles of H2O = 0.56 mol

Number of moles of CO2 = 0.62 mole

Number of moles of H2 = 0.61 mol

Volume = 2.0L

Step 3: Calculate Q

Pco = 0.13 / 1.92  P

Ph2o = 0.56 / 1.92 P

Pco2 = 0.62/1.92 P

Ph2 =0.61 / 1.92 P

Q =  [CO2][H2] / [CO][H2O] = 5.2

Q > Kp  The reaction will proceed to the left

The reaction will proceed in the reverse direction in order to increase the concentrations of both CO and H2O and decrease that of CO2 and H2 until Q = K.

To know more about concentrations of both CO and H2O

brainly.com/question/15237573

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Radda [10]

Answer: The new pressure is 3 psi.

Explanation:

Given: P_{1} = 12 psi,         T_{1} = 20^{o}C

P_{2} = ?,          T_{2} = 5^{o}C

Formula used is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi

Thus, we can conclude that the new pressure is 3 psi.

7 0
3 years ago
`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

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So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
3 years ago
How much CO2 is produced from the decomposition of 200g of CaCO3 if 112 of CaO are produced?
MArishka [77]
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What is the empirical formula for propene (C3H6)?<br> C2H4<br> C4H8<br> C3H6<br> CH2
melamori03 [73]

Answer:

C3H6

Explanation:

please mark me as brainlest

8 0
3 years ago
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