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Tju [1.3M]
1 year ago
7

The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal:CO(g) + H₂O(g) ⇄

CO₂(g) + H₂(g)At a given temperature, Kp = 2.7. If 0.13 mol of CO, 0.56 mol of H₂O, 0.62 mol of CO₂, and 0.43 mol of H₂ are put in a 2.0-L flask, in which direction does the reaction proceed?
Chemistry
1 answer:
lilavasa [31]1 year ago
8 0

The reaction will proceed in the reverse direction in order to increase the concentrations of both CO and H2O and decrease that of CO2 and H2 until Q = K.

The reaction will proceed to the left

Step 1: The balanced equation

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

Step 2: Data given

Kp = 2.7

Number of moles of CO = 0.13 mol

Number of moles of H2O = 0.56 mol

Number of moles of CO2 = 0.62 mole

Number of moles of H2 = 0.61 mol

Volume = 2.0L

Step 3: Calculate Q

Pco = 0.13 / 1.92  P

Ph2o = 0.56 / 1.92 P

Pco2 = 0.62/1.92 P

Ph2 =0.61 / 1.92 P

Q =  [CO2][H2] / [CO][H2O] = 5.2

Q > Kp  The reaction will proceed to the left

The reaction will proceed in the reverse direction in order to increase the concentrations of both CO and H2O and decrease that of CO2 and H2 until Q = K.

To know more about concentrations of both CO and H2O

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Answer:

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Explanation:

Given data:

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Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C  × 3.0°C

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What volume. In liters, of H2O(g) measured at STP is produced by the combustion of 15.63 g of natural gas (CH4) according to the
fomenos

Answer:

V = 43.95 L

Explanation:

Given data:

Mass of CH₄ decomposed = 15.63 g

Volume of H₂O produced at STP = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →       2H₂O  + CO₂

Number of moles of CH₄:

Number of moles = mass/molar mass

Number of moles = 15.63 g/ 16 g/mol

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Now we will compare the moles of H₂O with CH₄.

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                           1                 :                2

                        0.98             :            2×0.98 = 1.96 mol

Volume of hydrogen:

PV = nRT

1 atm × V = 1.96 mol × 0.0821 atm.L/mol.K × 273.15 K

V = 43.95atm.L / 1atm

V = 43.95 L

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