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ioda
3 years ago
5

what happens to gas molecules as the pressure is increased while the temperature and volume of the container remain constant acc

ording to the kinetic molecular theory
Chemistry
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer:

According to the kinetic molecular theory of gases, the average speed and kinetic energy of gas molecules would INCREASE.

Explanation:

In the kinetic molecular theory of gases, assumptions were made based on macroscopic properties of gas (pressure, volume and temperature) which are as a result of the microscopic properties like the position and the speed of the gas molecules. The kinetic molecular theory explains the behaviour of gases through the following 5 assumptions made about an ideal gas;

--> Molecules of a gas are in constant and rapid motion in straight lines until they collide with one another and with the walls of their containers.

--> The actual volume occupied by the had is negligible compared with the volume of the container.

--> Forces of attraction or repulsion between the molecules of a gas are negligible

--> The collision between the molecules is perfectly elastic.

--> The average kinetic energy of the gas molecules is proportional to the temperature of the gas.

Because gas molecules are in constant motion, it has kinetic energy which can be altered when there is increase in pressure. An increase in pressure will cause gas molecules to collide more frequently with one another. This in turn leads to increase in average speed and the kinetic energy of the individual molecules.

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A 0.479 g sample of nitrogen, oxygen or neon gas occupies a volume of 265 ml at 157 kpa and 20◦c. what is the molar mass and ide
Anna11 [10]
PV = nRT
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Answer:

\Delta _{fus}H=205J/g=13.03kJ/mol

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

Q=m*\Delta _{fus}H

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g

Or in kJ/mol:

\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\  \Delta _{fus}H=13026.93J/mol=13.03kJ/mol

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