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jonny [76]
3 years ago
10

How many moles of oxygen gas are produced from the decomposition of six moles of potassium

Chemistry
1 answer:
GREYUIT [131]3 years ago
4 0

From the equation, 32 equiv dixoygen gas evolve from 1 equiv chlorate.


You started with 6 equiv chlorate, and thus 9 equiv dioxygen gas are evolved. This is a common undergrad experiment. I think you need to add some sort of manganese oxide catalyst.

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A 31.5 g wafer of pure gold initially at 69.4 ∘C is submerged into 63.4 g of water at 27.4 ∘C in an insulated container.
liubo4ka [24]

Answer: The final temperature of both substances at thermal equilibrium is 301.0 K

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of gold = 31.5 g

m_2 = mass of water = 63.4 g

T_{final} = final temperature = ?

T_1 = temperature of gold = 69.4^oC=342.4K

T_2 = temperature of water = 27.4^oC=300.4K

c_1 = specific heat of gold = 0.129J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]

T_{final}=301.0K

The final temperature of both substances at thermal equilibrium is 301.0 K

4 0
3 years ago
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