Answer:
Height h = 37.8 m
Explanation:
Given
:
Velocity of car (v) = 98 km / h
Acceleration of gravity = 9.8 m/s²
Computation:
Acceleration of gravity = 9.8 m/s²
Acceleration of gravity = (98)(1,000 m / 3,600 s)
Acceleration of gravity = 27.22 m/s
By using law of conservation of energy
;
(1/2)mv² = mgh
h = v² / 2g
h = 27.22² / 2(9.8)
Height h = 37.8 m
Answer:
v = 79.2 m/s
Solution:
As per the question:
Mass of the object, m = 250 g = 0.250 kg
Angle, 
Coefficient of kinetic friction, 
Mass attached to the string, m = 0.200 kg
Distance, d = 30 cm = 0.03 m
Now,
The tension in the string is given by:
(1)
Also
T = m(g + a)
Thus eqn (1) can be written as:
Now, the speed is given by the third eqn of motion with initial velocity being zero:
where
u = initial velocity = 0
Thus
You may look at what group they are in
Group
1A=Group 1
2A = Group 2
3A = Group 13
4A= Group 14
5A=Group 15
6A=Group 16
7A=Group 17
The #A tells you how many valence electrons there are by the # before A. Such as Chlorine, which is in 7A, so therefore has 7 valence electrons.
Answer:
Is that an actual question for school?
Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*
3. A
The relation between V and I at constant R is;V=IR, so it is a direct linear relation.
4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.
Please note that y:x relations are always straight lines while relations are parabolic lines.
Hope this helps!
