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ivann1987 [24]
3 years ago
11

Snow is falling vertically at a constant speed of 7.3 m/s. At what angle from the vertical do the snowflakes appear to be fallin

g as viewed by the driver of a car traveling on a straight, level road with a speed of 60 km/h?
Physics
1 answer:
Burka [1]3 years ago
4 0

Answer:

23.7°

Explanation:

Uy = 7.3 m/s

Ux = 60 km/h = 16.67 m/s

\tan \alpha  =  \frac{7.3}{16.67}  \\  \alpha  =  \cot( \frac{7.3}{16.67} )

= 23.7°

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A proton and an electron are moving in the +x direction in a magnetic field in the +z
Aleksandr [31]

Answer:

Explanation:

Force on a moving charge is given by the following relation

F = q ( v x B )

for proton

q = e  ,   v = vi  , B = Bk

F = e ( vi x Bk )

= Bev - j

= - Bevj

The direction of force is along negative of y axis or -y - axis.

for electron

q = - e  ,   v = vi  , B = Bk

F = - e ( vi x Bk )

= - Bev - j

=  Bevj

The direction of force is along positive  of y axis or + y - axis.

5 0
3 years ago
What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s
Wittaler [7]
The formula is=1/2(m x v^2)

so = 1/2*(0.05)*(310)^2

ans is =2402.5 joules
3 0
3 years ago
Need help ASAP!! Thank you..
Nonamiya [84]
1.potential energy 2.kinetic energy 3.electrical energy 4.electrical energy
5 0
3 years ago
Read 2 more answers
Singly charged gas ions are accelerated from rest through a voltage of 10.3 V. At what temperature (in K) will the average kinet
Natasha_Volkova [10]

Answer:

Temperature of the gas molecules is 7.96 x 10⁴ K

Explanation:

Given :

Ions accelerated through voltage, V = 10.3 volts

The work done to change the position of singly charged gas ions is given by the relation :

W = q x V

Here q is charge of the ions and its value is 1.6 x 10⁻¹⁹ C.

Average kinetic energy of gas molecules is given by the relation:

K.E. = \frac{3}{2}kT

Here T is temperature and k is Boltzmann constant and its value is 1.38 x 10⁻²³ J/K.

According to the problem, the average kinetic energy of gas is equal to the work done to move the singly charged ions, i.e. ,

K.E. = W

\frac{3}{2}kT = qV

Rearrange the above equation in terms of T :

T= \frac{2qV}{3k}

Substitute the suitable values in the above equation.

T=\frac{2\times1.6\times10^{-19}\times10.3 }{3\times1.38\times10^{-23} }

T = 7.96 x 10⁴ K

5 0
3 years ago
A 7.59-m-tall container is filled to the brim, partway with mercury and the rest of the way with water. The container is open to
hoa [83]

Answer:

0.22 m

Explanation:

P_{o} = Atmospheric pressure = 101325 Pa

P = Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa

h = height of the container = 7.59 m

x = depth of the mercury

Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water

P = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\2 P_{o} = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\P_{o} = \rho _{w} g (h - x) + \rho _{hg} g x\\101325 = (1000) (9.8) (7.59 - x) + (13600) (9.8) x\\x = 0.22 m

5 0
3 years ago
Read 2 more answers
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