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Luba_88 [7]
3 years ago
15

an atom has 2 electrons in the first energy level, 8 electrons in the second energy level, and 1 electron in the third energy le

vel. What is the number of core electrons
Chemistry
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:2

Explanation:

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Help meh......please...
Mrrafil [7]

Answer:

The third one

Explanation:

Nickel-62 has the highest binding energy per nucleon of any isotope for any element. Isotopes heavier than 62Ni cannot be formed by nuclear fusion without losing energy.

3 0
3 years ago
What is the percentage of water in the following compound? answer using one decimal place. sodium carbonate decahydrate, na2co3
ehidna [41]

The percentage by mass of water in Na2CO3.10H2O from the calculation is  62.9%

<h3>What is percentage by mass?</h3>

The term percentage by mass refers to the amount of a particular moiety by mass in a molecule.

In this case, we know that the molar mass of Na2CO3.10H2O is 286 g/mol the molar mass of the 10 moles of water is 180 g/mol hence the percentage by mass of water in the compound is; 180 g/mol /286 g/mol  * 100/1 = 62.9%

Learn more about percentage by mass: brainly.com/question/16885872

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6 0
2 years ago
Read 2 more answers
A non-metallic atom(at.no. 9) forms a molecule of the same,containing a single covalent bond. give reason
bezimeni [28]
They are so may forms
4 0
3 years ago
How many moles of argon gas would be present in a 37.0 liter vessel at 45.00 °C at a pressure of 2.50 atm?
Pani-rosa [81]

Answer:

3.54 mol

Explanation:

Step 1: Given data

  • Volume (V): 37.0 L
  • Temperature (T): 45.00 °C
  • Pressure (P): 2.50 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 45.00°C + 273.15 = 318.15 K

Step 3: Calculate the number of moles (n) of argon gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol

8 0
3 years ago
A student titrated 20 ml of 0.410 m hcl with 0.320 m naoh. determine the volume of naoh needed at equivalence point
Aleksandr-060686 [28]

Answer:

25.6mL NaOH

Explanation:

We are given the Molarity of the solution (\frac{moles}{liters}) and the volume of the solution (.02L).

By multiplying the two together, we can find the moles of solution that are reacted with HCl.

moles = \frac{.410 moles}{L} *.02L

This gives us .0082 moles of HCl.

We then find the moles of NaOH that are needed to react with the HCl using the equation.

HCl + NaOH = NaCl + H_{2} O

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.

Dividing this value by the Molarity of the solution

\frac{.0082mol}{.320mol/L}

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.

3 0
3 years ago
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