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3 years ago

Question 1: Use the image and your knowledge of the isosceles triangle to find the value of x

Mathematics

1 answer:

pochemuha3 years ago

3 0

Answer:

35 degrees

Step-by-step explanation:

since both sides are equal, so are the angles involved.

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6+3×(13−2)−5^2<br><br> whoever answers first will get branliest and will get 50 points

KiRa [710]

Answer:

Step-by-step explanation:

8 0

3 years ago

Write the equation of the line parallel to<br> y=-2/3x+4 and through the point (–3, 15)

MrRa [10]

Parallel = same slope
y = -2/3x + b
Plug in point
15 = -2/3(-3) + b
15 = 2 + b, b = 13
Solution: y = -2/3x + 13

6 0

3 years ago

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Prove 2(2x+4)= 16 2(2x) by using the laws of exponents.<br> boris9

storchak [24]

The prove that the equation can be verified using the laws of exponents.

<h3>What is the proof of the equation given; 2^(2x+4)= 16 × 2^(2x)?</h3>

It follows from the task content that the equation given is; 2^(2x+4)= 16 • 2^(2x).

It follows from the laws of indices ; particularly, the product of same base numbers.

The evaluation is therefore as follows;

2^(2x+4)= 16 • 2^(2x)

2^(2x) • 2⁴ = 16 • 2^(2x)

2^(2x) • 16 = 16 • 2^(2x)

Hence, since LHS = RHS, it follows that the expression is mathematically correct.

Read more on laws of exponents;

brainly.com/question/847241

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1 year ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$