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Valentin [98]
3 years ago
15

Which number line shows the solution set for 18-201= 6?

Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

none

Step-by-step explanation:

this question does not make sense try to make it a number line

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Negative four times a number plus nine is no more than the number minus twenty one
marysya [2.9K]
N is no more than six
8 0
3 years ago
Read 2 more answers
Find
Sedaia [141]

Answer:

The amount of steel used = 94.38 m^{2}

Step-by-step explanation:

Height of the tank = 4.5 m.

Diameter of the tank = 4.2 m.

But,

radius = \frac{diameter}{2}

           = \frac{4.2}{2}

radius  = 2.1 m

Total surface area of a cylinder = 2\pirh + 2\pir^{2}

                                      = 2\pir(r + h)

                                      = 2 x \frac{22}{7} x 2.1 (2.1 + 4.5)

                                      = 44 x 0.3 (6.6)

                                      = 87.12

Total surface area of a cylinder = 87.12 m^{2}

Since \frac{1}{12} of the steel was wasted, then;

\frac{1}{12} x 87.12 = 7.26 m^{2}

Actual area of steel sheet used = 87.12 + 7.26

                                                     = 94.38 m^{2}

Thus, 94.38 m^{2} of steel was used in making the tank.

4 0
3 years ago
Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 7 liters of natural oil for every 5 liters of
Svetach [21]
What we know:
Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 7 liters of natural oil for every 5 liters of synthetic oil.

What we need to find:
If 355 liters of synthetic oil are used, how many liters of petrolyn oil will be made?

Set up a proportion to find how much natural oil is used.
7L natural oil/5L synthetic oil = x/355 synthetic oil where x=natural oil
7/5=x/355
(5)(x)=(7)(355) cross multiplied
5x=2485 simplified
5/5x=2485/5 multiplicative inverse
x=497L

Now, add both synthetic oil and natural oil to find amount of petrolyn oil.

355 L synthetic oil + 497 L natural oil= 852 L of petrolyn oil
5 0
3 years ago
Shreya and beth each improved their yards by planting rose bushes and ornamental grass. They brought their supplies from the sam
frutty [35]

Answer:

  • <u><em>The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.</em></u>

Explanation:

Name the variables and build a system of two equations with two unknowns.

<u>1. Variable r</u>: cost of one rose bush

<u>2. Variable g</u>: cost of one bunch of ornamental grass.

<u>3. First equation</u>:

  • Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

        4r + 4g = 68

<u>4. Second equation</u>:

  • Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

  • 11r + 2g = 115

<u>5. System of equations</u>:

  • 4r + 4 g = 68     equation 1
  • 11r + 2g = 115     equation 2

<u>6. Solve the system</u>

a) Divide the equation 1 by 2:

  • 2r + 2g  =  34     equation 1a
  • 11r + 2g = 115     equation 2

b) Subtract equation 1a from equation 2:

  • 11r - 2r = 115 - 34
  • 9r = 81
  • r = 81 / 9
  • r = 9

c) Substitute the value of r into the equation 1a:

  • 2(9) + 2g = 34
  • 9 + g = 17
  • g = 17 - 9
  • g = 8

<u>7. Conclusion</u>:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

7 0
3 years ago
Please look at the image which includes the question ! I need help on this. I am pretty confused right now.
vlabodo [156]
I'm guessing it's (8,9)
5 0
2 years ago
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