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blondinia [14]
3 years ago
13

Shortly after exercising ________, people become less restrained in their aggressive responses to provocation.

Physics
1 answer:
BaLLatris [955]3 years ago
4 0
Shortly after exercising self-control, people become less restrained in their aggressive responses to provocation. If you learn how to control yourself, your life with other people will be much easier. You will know how to deal with provocation better, and not to be so stressed out about it. You will know when to stand up for yourself, and when to keep quiet.

-Hope this helped.
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In the figures below, there are four copper wires shown. Assuming that all the wires are the same temperature, which has the gre
hichkok12 [17]
The speed of the ball is how hard you hit it
8 0
3 years ago
A 2120 kg car traveling at 13.4 m/s collides with a 2810 kg car that is initally at rest at a stoplight. The cars stick together
viktelen [127]

Answer:

The coefficient of friction between the cars and the road is 0.859.

Explanation:

The two cars collide each other inelastically, then we can determine the resulting velocity by the Principle of Momentum Conservation:

m_{A}\cdot v_{A} + m_{B}\cdot v_{B} = (m_{A} + m_{B})\cdot v (1)

Where:

m_{A}, m_{B} - Masses of the cars, in kilograms.

v_{A}, v_{B} - Initial velocities of the cars, in meters per second.

v - Velocity of the resulting system, in meters per second.

If we know that m_{A} = 2120\,kg, v_{A} = 13.4\,\frac{m}{s }, m_{B} = 2810\,kg and v_{B} = 0\,\frac{m}{s}, then the  velocity of the resulting system:

v = \frac{m_{A}\cdot v_{A}+m_{B}\cdot v_{B}}{m_{A}+m_{B}}

v = \frac{(2120\,kg)\cdot \left(13.4\,\frac{m}{s} \right)+(2810\,kg)\cdot \left(0\,\frac{m}{s} \right)}{2120\,kg + 2810\,kg}

v = 5.762\,\frac{m}{s}

By Principle of Energy Conservation and Work-Energy Theorem, we understand that the initial translational kinetic energy (K), in joules, is dissipated due to work done by friction (W_{f}), in joules, that is to say:

K = W_{f} (2)

\frac{1}{2}\cdot (m_{A}+m_{B})\cdot v^{2} = \mu\cdot (m_{A}+m_{B})\cdot g \cdot s

\frac{1}{2}\cdot v^{2} = \mu \cdot g\cdot s (2b)

Where:

\mu - Coefficient of friction, no unit.

g - Gravitational acceleration, in meters per square second.

s- Travelled distance, in meters.

If we know that v = 5.762\,\frac{m}{s}, g = 9.807\,\frac{m}{s^{2}} and s = 1.97\,m, then the coefficient of friction is:

\mu = \frac{v^{2}}{2\cdot g\cdot s}

\mu = \frac{\left(5.762\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1.97\,m)}

\mu = 0.859

The coefficient of friction between the cars and the road is 0.859.

6 0
3 years ago
(please help asap)
OLEGan [10]

Answer:

A. Yard

Explanation:

Should be correct lol :)

6 0
3 years ago
Read 2 more answers
A car of mass 1000 kg is travelling at 10 m/s. What is its kinetic energy?
Marysya12 [62]

Answer:

50,000

Explanation:

kinetic energy=1\2×mv^2

=1\2×1000kg×10×10

=50000

6 0
3 years ago
The different between capactance wnd capacitor
velikii [3]

Answer:

The parallel plate capacitor is the simplest form of capacitor. ... The property of a capacitor to store charge on its plates in the form of an electrostatic field is called the Capacitance of the capacitor. Not only that, but capacitance is also the property of a capacitor which resists the change of voltage across it.

Explanation:

credits :- adultsscience

8 0
3 years ago
Read 2 more answers
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