<h2>Given :-</h2>
Initial speed (v) = 1.9m/s
Final speed (u) = 3.8m/s
Time (t) = 11 s
<h2>Formula Used :-</h2>
(a = acceleration)
➾ 
<h2>Solution:-</h2>
(putting the value of v, u and t from above)
➾ 
➾ 
➾ 
Therefore, the acceleration rate = 0.17m/s.
-2(x+14)+1=15
distribute
-2x - 14 + 1 = 15
add 14 to each side
-2x + 1 = 29
subtract one from each side
-2x = 28
divided by -2
x = -14
10 millimeters in a centimeters.
10.5*10=105
If you would like to solve the following system of equations, you can do this like this:
y = - 2 * x + 7
y = 1/3 * x
____________
1/3 * x = - 2 * x + 7
1/3 * x + 2 * x = 7
1/3 * x + 6/3 * x = 7
7/3 * x = 7 /*3/7
x = 7 * 3 / 7
x = 3
y = 1/3 * x = 1/3 * 3 = 1
The correct result would be: x = 3 and y = 1.
Answer:
A. Every minute, 2/3 of a gallon is drained, so the rate of change would be -2/3
B. It would take 7.5 minutes to drain the tank
