Answer:
The number of turns of the solenoid is 3536 turns
Explanation:
Given;
magnetic field of the solenoid, B = 0.1 T
current in the solenoid, I = 1.8 A
length of the solenoid, L = 8cm = 0.08m
The magnetic field near the center of the solenoid is given by;
B = μ₀nI
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
n is number of turns per length
I is the current in the coil
The number of turns per length is calculated as;
n = B / μ₀I
n = (0.1 ) / (4π x 10⁻⁷ x 1.8)
n = 44203.95 turns/m
The number of turns is calculated as;
N = nL
N = (44203.95)(0.08)
N = 3536 turns
Therefore, the number of turns of the solenoid is 3536 turns
<span>newton say that she must use her hand to put up the cup because the work is equal to force times it distance, that is in the same direction of the force applied. if carole used her hand to put up the cup, then he is not applying any work because the displacement is not in the same direction of the force</span>
The energy of position, stored energy. e.g. exhibited by the position of electrons in electron shells relative to the atom's nucleus.
Answer:
pretty sure its B if it isnt im so so sorry
Explanation:
The general formula for the frequency of the nth-harmonic of the column of air in the tube is given by

where f1 is the fundamental frequency.
In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are


so their difference is

So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is: