The more powerful an appliance is, the more amounts of energy it uses. For instance a jack hammer that does not create a lot of destruction or change does not use a lot of energy. If a jack hammer that creates a lot of destruction and change probably uses a lot more energy and makes more sound.
Answer:
T=+1.133N
Explanation:
Tension and weight are forces that have opposite directions
Weight is negative (downward)
W=m*g= 0.11kg*(-9.8m/s^2)
W= -1.078N
Tension is possitive (upward)
The total force will be the sum of both (the difference taking in consideration the direction)
Ft= T+W
Also the total force is the product of the mass due to acceleration:
Ft=m*a
Ft= +0.11kg*0.5m/s^2
Ft=+0.055N (upward)
Tension will be the difference between Ft and W:
T= Ft-W
T=+0.055N-(-1.078N)
T=+1.133N
Answer:
6 seconds
0.167 Hz
Explanation:
Distance = 4 m
Velocity = 0.75 m/s
Period is given by
The period of the motion is 3 seconds
Frequency is given by
The frequency of the motion is 0.33 Hz
Acceleration = (change in speed) / (time for the change)
change in speed = (speed at the end) - (speed at the beginning)
Our cyclist's change in speed = (3 m/s) - (8 m/s) = -5 m/s
Acceleration = (-5 m/s) / (60 seconds)
<em>Acceleration = -1/12 m/s²</em>
The partial pressures of HBr when the system reaches equilibrium is 2.4 X 10⁻¹¹ atm
<u>Explanation:</u>
H₂ + Br₂ ⇒ 2HBr
PH₂ = 0.782atm
PBr₂ = 0.493atm
Kp = (PHBr)²/ (PH₂) (PBr₂) = 1.4 X 10⁻²¹
At equilibrium:
Let 2x = pressure of HBr
PH₂ = 0.782 -x
PBr₂ = 0.493 - x
Kp = (2x)^2 / (0.782-x)(0.493-x)
Now, because Kp is very small, x will be very small compared to 0.782 and 0.493.
Then,
Kp = 1.4X10⁻²¹ = (4x²) / (0.782)(0.493)
x = 1.2X10⁻¹¹
PHBr = 2x = 2.4 X 10⁻¹¹ atm
Therefore, the partial pressures of HBr when the system reaches equilibrium is 2.4 X 10⁻¹¹ atm
