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FromTheMoon [43]
3 years ago
6

Voltage can be provided by

Physics
1 answer:
kodGreya [7K]3 years ago
5 0
All of these can provide voltage. a battery is a generator, and plugging in to an electrical outlet is just like your phone charger or TV..
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Who ever answers Frist get marked the Brainly Est
natka813 [3]

Answer:

Explanation:

It would actually be A. 30 , as each hour of ascension (i am not sure about the correct terminology) equals 15 .

3 0
2 years ago
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Consider each of the electric- and magnetic-field orientations given next. In each case, what is the direction of propagation of
vodka [1.7K]

The route of the propagation of the wave in every case are; A) +z route B) +z route C) -y route D) -x route .

vec Ein is the Electrical area vector and vec Bin is the Magnetic area vector, due to the fact the sphere vectors are continually perpendicular to every different the propagation of the wave is perpendicular to the 2 vectors. The route of the propagation of the wave may be observed with the aid of using vec Ein X vec Bin (Cross made from vectors). This also can be achieved with the aid of using the usage of the RIGHT HAND RULE.

Cross product may be observed with the aid of using

i x j = okay and j x i = - okay

j x okay=i and okay x j = - i

okay x i=j and that i x okay = - j

wherein i represents the +x route, j represents the +y route and okay represents the +z route

The RIGHT HAND RULE may be used to demonstrate the move product with the aid of using the usage of the proper hand and pointing the index finger withinside the route of the primary vector and the center finger alongside the second one vector, the move product is withinside the route of the thumb.

A) vec Ein the +xdirection,vec Bin the +ydirection,

Finding the move made from the 2 vectors (i x j = okay) might provide a vector withinside the +z route

B) vec Ein the -y route,vec Bin the +x route

Finding the move made from the 2 vectors (- j x i = okay) might provide a vector withinside the +z route

C) vec Ein the +z route,vec Bin the -x route

Finding the move made from the 2 vectors (okay x - i = - j) might provide a vector withinside the -y route

D) vec Ein the +y route,vec Bin the -z route

Finding the move made from the 2 vectors (j x - okay = - i) might provide a vector withinside the -x route

The complete question is- Consider each of the electric- and magnetic-field orientations given next. In each case, what is the direction of propagation of the wave?A)\vec Ein the +xdirection,\vec Bin the +ydirection.Please Choose+ x direction- x direction+ y direction- y direction+ z direction- z directionB)\vec Ein the -y direction,\vec Bin the +x directionPlease Choose+ x direction- x direction+ y direction- y direction+ z direction- z directionC)\vec Ein the +z direction,\vec Bin the -x direction.Please Choose+ x direction- x direction+ y direction- y direction+ z direction- z directionD)\vec Ein the +y direction,\vec Bin the -z direction.Please Choose+ x direction- x direction+ y direction- y direction+ z direction- z direction.

Learn more about vector here-

brainly.com/question/13966790

#SPJ4

3 0
1 year ago
A ball rolls along the floor with a constant velocity of 6m/s how far it have to gone after 50 seconds
Alika [10]
50(6)=300.
The ball traveled 300 meters in 50 seconds.
Hope this helps and please give brainliest!
8 0
3 years ago
Need help! Thanks for whoever answers.
Hunter-Best [27]

Answer:

2021 + 100000000

Explanation:

i o g kk ybb

5 0
3 years ago
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An RLRL circuit with with a 1212-ΩΩ resistor and a 0.06−H0.06−H inductor carries a current of 1A1A at t=0t=0, at which time a vo
tankabanditka [31]

Answer:

The equation of current is I=0.86 cos \left (120 t + \frac{\pi}{2}  \right )

Explanation:

Resistance, R = 12 ohm

Inductance, L = 0.06 H

E (t) = 12 cos (120 t)

Compare with the standard equation,

E=E_{0}cos (2\pi ft)

2\pi ft = 120 t \\\\\\w = 2\pi f = 120 rad/s

So, the inductive reactance is

XL = w L = 120 x 0.06 = 7.2 ohm

The impedance of the circuit is

Z =\sqrt{12^2+7.2^2}\\\\Z = 14 ohm

The current leads  by 90degree so the equation of current is

I=\frac{Eo}{Z} cos \left (120 t + \frac{\pi}{2}  \right )\\\\I=\frac{12}{14} cos \left (120 t + \frac{\pi}{2}  \right )\\\\I=0.86 cos \left (120 t + \frac{\pi}{2}  \right )

4 0
3 years ago
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