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daser333 [38]
3 years ago
10

A string is attached to a ball that has a mass of 0.11 kg. A student pulls up on the string so that the ball accelerates upward

at 0.5 m/s2. What is the tension in the string? (Take the magnitude of acceleration due to gravity to be 9.8 m/s2.)
(Hint: How do all the forces involved interact with each other?)
Physics
1 answer:
enot [183]3 years ago
7 0

Answer:

T=+1.133N

Explanation:

Tension and weight are forces that have opposite directions

Weight is negative (downward)

W=m*g= 0.11kg*(-9.8m/s^2)

W= -1.078N

Tension is possitive (upward)

The total force will be the sum of both (the difference taking in consideration the direction)

Ft= T+W

Also the total force is the product of the mass due to acceleration:

Ft=m*a

Ft= +0.11kg*0.5m/s^2

Ft=+0.055N (upward)

Tension will be the difference between Ft and W:

T= Ft-W

T=+0.055N-(-1.078N)

T=+1.133N

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Name three types of stress that a force can cause inside an object?
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The valu
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Answer:

\% Error = 2.6\%

Explanation:

Given

x: 1.54, 1.53, 1.44, 1.54, 1.56, 1.45

Required

Determine the percentage error

First, we calculate the mean

\bar x = \frac{\sum x}{n}

This gives:

\bar x = \frac{1.54+ 1.53+ 1.44+ 1.54+ 1.56+ 1.45}{6}

\bar x = \frac{9.06}{6}

\bar x = 1.51

Next, calculate the mean absolute error (E)

|E| = \sqrt{\frac{1}{6}\sum(x - \bar x)^2}

This gives:

|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}

|E| = \sqrt{\frac{1}{6}*0.0132}

|E| = \sqrt{0.0022}

|E| = 0.04

Next, calculate the relative error (R)

R = \frac{|E|}{\bar x}

R = \frac{0.04}{1.51}

R = 0.026

Lastly, the percentage error is calculated as:

\% Error = R * 100\%

\% Error = 0.026 * 100\%

\% Error = 2.6\%

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