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daser333 [38]
3 years ago
10

A string is attached to a ball that has a mass of 0.11 kg. A student pulls up on the string so that the ball accelerates upward

at 0.5 m/s2. What is the tension in the string? (Take the magnitude of acceleration due to gravity to be 9.8 m/s2.)
(Hint: How do all the forces involved interact with each other?)
Physics
1 answer:
enot [183]3 years ago
7 0

Answer:

T=+1.133N

Explanation:

Tension and weight are forces that have opposite directions

Weight is negative (downward)

W=m*g= 0.11kg*(-9.8m/s^2)

W= -1.078N

Tension is possitive (upward)

The total force will be the sum of both (the difference taking in consideration the direction)

Ft= T+W

Also the total force is the product of the mass due to acceleration:

Ft=m*a

Ft= +0.11kg*0.5m/s^2

Ft=+0.055N (upward)

Tension will be the difference between Ft and W:

T= Ft-W

T=+0.055N-(-1.078N)

T=+1.133N

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Answer:

<u>1.8kJ</u>

Explanation:

Formula :

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<u />

===============================================================

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=============================================================

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2 years ago
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The velocity of the transverse waves produced by an earthquake is 5.05 km/s, while that of the longitudinal waves is 8.585 km/s.
sattari [20]

Answer:

d=691.71km

Explanation:

The time lag between the arrival of transverse waves and the arrival of the longitudinal waves is defined as:

t=\frac{d}{v_t}-\frac{d}{v_l}

Here d is the distance at which the earthquake take place and v_t, v_l is the velocity of the transverse waves and longitudinal waves respectively. Solving for d:

t=d(\frac{1}{v_t}-\frac{1}{v_l})\\d=\frac{t}{\frac{1}{v_t}-\frac{1}{v_l}}\\d=\frac{56.4s}{\frac{1}{5.05\frac{km}{s}}-\frac{1}{8.585\frac{km}{s}}}\\d=691.71km

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Answer:

35.7kJ

Explanation:

we can calculate the amount of heat energy required , using this formula

Q = mcθ

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Q = heat energy (Joules, J)  

m = mass of a substance (kg)  

c = specific heat capacity (units Jkg^{-1} C^{-1})

θ  = change in temperature (Celcius,C or Kelvin K)

Assume Specific heat capacity (c) of water =4200Jkg^{-1} C^{-1}

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3 years ago
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