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3 years ago

Jim mowed 5/9 of a lawn. Sarah mowed 1/3 of the lawn. What fraction of the lawn remained to be mowed?

Mathematics

1 answer:

Montano1993 [528]3 years ago

8 0

Answer:

1/9

Step-by-step explanation:

Because 1/3 is the same as 3/9, 5/9 + 3/9 = 8/9. so then 9/9 - 8/9 = 1/9. Giving them 1/9 of the lawn remained to be mowed.

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Solve the following equation. Then place the correct mixed number in the box provided. 5x/7=22

natka813 [3]

We have that
<span> 5x/7=22
multiply by 7 both sides
5x=22*7-------> 5x=154
divide by 5 both sides
x=154/5
x=30.8--------> x=30 4/5

the answer is
x=30 4/5</span>

7 0

4 years ago

Two forces of 19.8 pounds and 36.5 pounds act on a body with an angle of 61.4 degrees between them.

murzikaleks [220]

<h2>ANSWER:</h2><h2>49.2 </h2>

Based on your question Two forces of 19.8 pounds and 36.5 pounds act on a body with an angle of 61.4 degrees between them.

After setting up the vectors on the plane and doing the required math

The answer is 49.2 pounds

<h2 />

4 0

3 years ago

Read 2 more answers

a recipe called for 6/8 cups of sugar for the cupcakes and another 2/8 cups for the icing. What is the total amount of sugar nee

Elina [12.6K]

9/8 or 1 1/2 hope that helps

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3 years ago

Answer question 14 please

Fittoniya [83]

Answer:

Step-by-step explanation:

Z is the only relation that does not pass the vertical line test, so Z is not a function.

Answer: D

7 0

2 years ago