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IceJOKER [234]
3 years ago
10

Help pleasee i’m stuck not sure how to find it.

Chemistry
2 answers:
balu736 [363]3 years ago
4 0

Answer:

c

Explanation:

pls brainliest me

Nat2105 [25]3 years ago
3 0
Girl I’m cunfus but yeah
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Please i need help really quickly on this. thank you​
prohojiy [21]

Answer:

the error could have been the fact that the unit for volume wasn't changed from cm³ to dm³

hence the calculation error

the solution to this would be first dividing the volume by 1000 to get that same amount in dm³ which is the standard unit to be used for volume-density calculations

6 0
3 years ago
5. If an atom has 35 protons in the nucleus, how many electrons will it have orbiting the
Aleks04 [339]

Answer:

35

Explanation:

An atom is neutral, meaning that the number of protons is equal to the number of electrons.

4 0
3 years ago
One mole of which substance contains a total of 6.02 x 1023 atoms? (I need help please.)
Korolek [52]

Answer:

Oxygen

Explanation:

One mole of atoms of oxygen has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02 X 1023 atoms of oxygen.

8 0
2 years ago
lighting a match results in light and heat since energy was not created by the match what transformation took place
Contact [7]

It is a chemical reaction


7 0
3 years ago
Read 2 more answers
On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?
enot [183]

Answer:

The answer is "2%"

Explanation:

Equation:

HNO_2\ (aq) \leftrightharpoons  H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\  K_a = 4.0\times \ 10^{-4}

H^{+}=?

Formula:

Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}

Let

[H^{+}] = [NO_2^{-}] = x at equilibrium

x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \  M\\\\

therefore,

[H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M

Calculating the % ionization:

= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\

6 0
3 years ago
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