The frequency of a simple harmonic oscillator such as a spring-mass system is given by
![f= \frac{1}{2 \pi} \sqrt{ \frac{k}{m} }](https://tex.z-dn.net/?f=f%3D%20%5Cfrac%7B1%7D%7B2%20%5Cpi%7D%20%20%20%5Csqrt%7B%20%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20)
where
k is the spring constant
m is the mass attached to the spring.
Re-arranging the formula, we get:
![m= \frac{k}{4 \pi^2 f^2}](https://tex.z-dn.net/?f=m%3D%20%5Cfrac%7Bk%7D%7B4%20%5Cpi%5E2%20f%5E2%7D%20)
and since we know the constant of the spring:
![k=39.5 N/m](https://tex.z-dn.net/?f=k%3D39.5%20N%2Fm)
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
Answer:
Because you have a greater understanding of the mentality and conduct of individuals you care about, you are better able to understand their perspective and are more likely to recognize possible situational factors for their behavior.
Answer:
![{2 \times 10} - 7 = 12 {}^{2} \div x \\ x = 2 \times 10 - 7 \div 12 {}^{2}](https://tex.z-dn.net/?f=%20%7B2%20%5Ctimes%2010%7D%20-%207%20%3D%2012%20%7B%7D%5E%7B2%7D%20%20%5Cdiv%20x%20%5C%5C%20x%20%3D%202%20%5Ctimes%2010%20-%207%20%5Cdiv%2012%20%7B%7D%5E%7B2%7D%20)
I'm just in jss2 but I read physics. this is what I think
Answer:
The answer is 11N to the right
Explanation:
Because 4N-3N= 1N
Therefore, 12N-1N=11N
The netforce is 11N to the right, because the greatest force is 12N to the right so it is more likely that the object is being pulled to the right.
Answer:
![1600 \frac{m}{s^2}](https://tex.z-dn.net/?f=1600%20%5Cfrac%7Bm%7D%7Bs%5E2%7D)
Explanation:
Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:
![a = \frac{change-in-velocity}{time} = \frac{Vf-Vi}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bchange-in-velocity%7D%7Btime%7D%20%3D%20%5Cfrac%7BVf-Vi%7D%7Bt%7D)
Where Vf is the final velocity of the object, (in our case 80 m/s)
Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)
and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.
Therefore we have:
![a = \frac{80 m/s - 0 m/s}{0.05 sec} = 1600 \frac{m}{s^2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B80%20m%2Fs%20-%200%20m%2Fs%7D%7B0.05%20sec%7D%20%3D%201600%20%5Cfrac%7Bm%7D%7Bs%5E2%7D)
Notice that the units of acceleration in the SI system are
(meters divided square seconds)