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Annette [7]
3 years ago
12

If a 1-megaton nuclear weapon is exploded

Physics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

1,780,000 N

Explanation:

0.2 atm × (1.013×10⁵ Pa/atm) = 20,260 Pa

Force = pressure × area

F = 20,260 Pa × (3.89 m × 22.6 m)

F = 1,780,000 N

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A 0.3-m-radius automobile tire rotates how many revolutions after starting from rest and accelerating at a constant 2.13 rad/s2
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Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

\theta = \omega_i  \ + \frac{1}{2} \alpha t^2

the initial angular velocity is zero,

\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad

Find how many revolutions that are in 573.2256 Rad

N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions

Therefore, the automobile tire rotates 91 revolutions

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