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Naya [18.7K]
3 years ago
5

What is the power output of an electric motor that lifts a 2.0 kilogram block 15 meters vertically in 6.0 seconds

Physics
1 answer:
Hatshy [7]3 years ago
5 0
<span>
power output 
= work done / time
= 2 * 9.81 * 15 / 6
= 49.05W
answer
4.49 W</span>
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Clarify what you mean by ratios?
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3 years ago
if the instantaneous current in the circuit is giveen by I=3 sin theta amperes, the rms value of the current will be
Kisachek [45]

Answer:

I_{rms}=2.12\ A

Explanation:

Given that,

The instantaneous current in the circuit is giveen by :

I=3\sin\theta\ A

We need to find the rms value of the current.

The general equation of current is given by :

I=I_o\sin\theta

It means, I_o=3\ A

We know that,

I_{rms}=\dfrac{I_o}{\sqrt2}\\\\=\dfrac{3}{\sqrt2}\\\\=2.12\ A

So, the rms value of current is 2.12 A.

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An object that is completely or partially submerged in fluid experience an upward force called?​
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The buoyant force or upward buoyancy force
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All phase changes are .an example of a phase change is an ice cube melting
masha68 [24]

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8 0
3 years ago
The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5
ValentinkaMS [17]

The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

<h3>Acceleration of the box</h3>

The acceleration of the box is calculated as follows;

vf² = vi² + 2as

a = (vf² - vi²)/2s

a = (11.5² - 13²) / (2 x 8.5)

a = -2.16 m/s²

<h3>Time of motion of the box</h3>

The time taken for the box to travel is calculated as follows;

a = (vf - vi)/t

t = (vf - vi) / a

t = (11.5 - 13) / (-2.16)

t = 0.69 s

<h3>Average power supplied by the friction</h3>

P = Fv

P = (ma)(vf - vi)

P = (1 x -2.16) x (11.5 - 13)

P = 3.24 W

Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

Learn more about average power here: brainly.com/question/19415290

#SPJ1

7 0
2 years ago
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