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schepotkina [342]
3 years ago
6

How many electrons in Titanium (Ti)

Physics
1 answer:
KengaRu [80]3 years ago
8 0

Answer:22

Explanation:

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Consider the two-body situation at the right. A 3.50x103-kg crate (m1) rests on an inclined plane and is connected by a cable to
4vir4ik [10]

Answer:a=2.42 m/s^2

Explanation:

Given

mass m_1=3.50\times 10^{3} kg

m_2=1.00\times 10^{3} kg

\theta(inclination)=30^{\circ}

\mu =0.21

Let T be the tension in the rope

From Diagram

m_1g\sin \theta -T-f_r=m_1a-----------------1

where f_r=friction\ force

f_r=\mu m_g\cos \theta

For block m_2

T=m_2a-----------2

From 1 & 2

m_1g\sin \theta -m_2a-\mu m_1g\cos \theta =m_1a

m_1g(\sin \theta -\mu \cos \theta )=(m_1+m_2)a

\frac{9.8\times 3.5\times 10^3}{4.5\times 10^3}(0.5-\0.21\cos 30)=4.5a

a=2.42 m/s^2

4 0
4 years ago
The kinetic energy of a baseball that with a mass of 0.140kg is 7 J. What is the baseballs velocity?
Nuetrik [128]

Answer:

10 m/s

Explanation:

Kinetic energy= \frac{1}{2}mv² where m is mass and v is velocity.

We have to make v the subject so we should rearrange the equation

K=\frac{1}{2}mv²

v²= \frac{K}{0.5*m} (use algebra)

v²= 7/0.5×0.140

v²=100

v=√100

v=10 m/s

We can confirm this by using the kinetic energy formula.

K=\frac{1}{2}×0.140×10²

K= 7 J

Hence it is proved that velocity is 10 m/s

3 0
1 year ago
At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and s
mash [69]

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

\frac{I1}{I2}  = (\frac{R2}{R1})^{2}   .............1

here I is intensity

so here I1 = 25

because for  0 to 25 there is  no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

so

\frac{I1}{I2}  = (\frac{R2}{R1})^{2}

\frac{25}{5}  = (\frac{41}{R1})^{2}

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

6 0
3 years ago
Molecules are bonded together in which of the following states of matter?
Inessa05 [86]
Solid is one of the three main states of matter, along with liquid and gas. Matter is the "stuff" of the universe, the atoms, molecules and ions that make up all physical substances. In a solid, these particles are packed closely together and are not free to move about within the substance.
6 0
3 years ago
A block of mass M on a horizontal surface is connected to the end of a massless spring of spring constant k. The block is pulled
slamgirl [31]

Answer:

Minimum coefficient of kinetic friction between the surface and the block is \mu_k=\frac{kx}{2Mg} .

Explanation:

Given:

Mass of the block = M

Spring constant = k

Distance pulled = x

According to the question:

<em>We have to find the minimum co-efficient of kinetic friction between the surface and the block that will prevent the block from returning to its equilibrium with non-zero speed.  </em>

So,

From the FBD we can say that:

⇒ Normal force, N=Mg                                   <em>...equation(i)</em>

⇒ Elastic potential energy, PE = \frac{kx^2}{2}               <em>  ...equation (ii)</em>

⇒ Frictional force, f = \mu_kN                                <em> ...equation (iii)</em>

⇒ Plugging (i) in (iii).

⇒ f=\mu_kMg

Now,

⇒ As we know that the energy lost due to friction is equivalent to PE .

⇒ PE=fx                     <em>...considering PE as</em> mgh or f(x) .

   Arranging the equation.

⇒ \frac{kx^2}{2}=\mu_k Mg (x)

⇒ \frac{kx}{2}=\mu_k Mg                 <em>...eliminating x from both sides.</em>

⇒ \frac{kx}{2Mg}=\mu_k                    <em>...dividing both sides wit Mg.</em>

Minimum coefficient of kinetic friction between the surface and the block is \frac{kx}{2Mg}=\mu_k .

4 0
4 years ago
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