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alexandr1967 [171]
2 years ago
9

A baseball is tossed straight up in the air. The table shows the height and velocity of the ball at different times as it moves

through the air.
Time in Air (seconds) Height of Ball Above Ground (feet) Velocity

(feet per second)

0.00 4 32

0.25 11 24

0.50 16 16

0.75 19 8

1.00 20 0

1.25 19 −8

1.50 16 −16

1.75 11 −24

2.00 4 −32

Which statement is true about the kinetic energy of the baseball at the moment it reaches its maximum height?


The baseball's kinetic energy is less than zero at that instant.


At that moment, all the baseball's kinetic energy has been lost as heat to the atmosphere.


The baseball's kinetic energy is greater than zero at that instant.


✅ At that moment, all the baseball's kinetic energy has been converted to potential energy. (correct answer)
Physics
1 answer:
Akimi4 [234]2 years ago
3 0

Answer: At that moment, all the baseball's kinetic energy has been converted to potential energy.

Explanation: I took the test

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Ace Manufacturing ordered 17 boxes with 85 ball bearings each.They also ordered 15 boxes with 90 spring each. How many more ball
photoshop1234 [79]

<u>Answer</u>

95


<u>Explanation</u>

One box has 85 ball bearings.

17 boxes = 17 × 85

               = 1,445 ball bearing


One contains 90 springs

15 boxes ⇒ 15 × 90

               ⇒ 1,350 spring


Number of ball bearing more than springs are;

1445 - 1350 =<em> 95</em>

3 0
4 years ago
The voltage across a 5-uF capacitor is: v (t )equals 10 cos open parentheses 6000 t close parentheses space straight V. What is
mamaluj [8]

Answer:

- 0.3sin6000t A

Explanation:

Voltage, v = 10 cos 6000t V

Capacitance = 5-uF

Current flowing through, i(t)

i(t) = c * d/dt (V)

c = 5-uF = 5 * 10^-6 F

i(t) = (5 * 10^-6) * d/dt(10 cos 6000t)

d/dt(10 cos 6000t) = (10 * 6000) * (-sin 6000t)

Hence,

i(t) = (5*10^-6) * (10*6000) * (-sin 6000t)

i(t) = 5*10^-6 * 6*10^4 * - sin6000t

i(t) = 30 * 10^-2 * - sin6000t

i(t) = 0.3*-sin6000t

i(t) = - 0.3sin6000t Ampere

4 0
3 years ago
On the sonometer shown below, a horizontal cord of length 5 m has a mass of 1.45 g. When the cord was plucked the wave produced
Korolek [52]

Answer:

(a) T = 0.015 N

(b) M = 1.53 x 10⁻³ kg = 1.53 g

Explanation:

(a) T = 0.015 N

First, we will find the speed of waves:

v =f\lambda

where,

v = speed of wave = ?

f = frequency = 120 Hz

λ = wavelength = 6 cm = 0.06 m

Therefore,

v = (120 Hz)(0.06 m)

v = 7.2 m/s

Now, we will find the linear mass density of the coil:

\mu = \frac{m}{l}

where,

μ = linear mass density = ?

m = mass = 1.45 g = 1.45 x 10⁻³ kg

l = length = 5 m

Thereforre,

\mu = \frac{1.45\ x\ 10^{-3}\ kg}{5\ m}\\\\\mu = 2.9\ x\ 10^{-4}\ kg/m

Now, for the tension we use the formula:

v = \sqrt{\frac{T}{\mu}}\\\\7.2\ m/s = \sqrt{\frac{T}{2.9\ x\ 10^{-4}\ kg/m}}\\\\(51.84\ m^2/s^2)(2.9\ x\ 10^{-4}\ kg/m) = T

<u>T = 0.015 N</u>

<u></u>

(b)

The mass to be hung is:

T = Mg\\\\M = \frac{T}{g}\\\\M = \frac{0.015\ N}{9.8\ m/s^2}\\\\

<u>M = 1.53 x 10⁻³ kg = 1.53 g</u>

4 0
3 years ago
Why is there no electric field at the center of a charged spherical conductor?
Alja [10]
I reported this question by accident, I am sorry.

Anyways, there is no electric field at the center of a charged spherical conductor because all the charged particles are at the edges and because of the complete cancellation everywhere.
5 0
3 years ago
Which was NOT a feature of welfare reform
qaws [65]
HeLLo tHeRe!

Your answer should be public transportation vouchers

Hope this helps. 
Have a nice day.


8 0
4 years ago
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