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alexandr1967 [171]
2 years ago
9

A baseball is tossed straight up in the air. The table shows the height and velocity of the ball at different times as it moves

through the air.
Time in Air (seconds) Height of Ball Above Ground (feet) Velocity

(feet per second)

0.00 4 32

0.25 11 24

0.50 16 16

0.75 19 8

1.00 20 0

1.25 19 −8

1.50 16 −16

1.75 11 −24

2.00 4 −32

Which statement is true about the kinetic energy of the baseball at the moment it reaches its maximum height?


The baseball's kinetic energy is less than zero at that instant.


At that moment, all the baseball's kinetic energy has been lost as heat to the atmosphere.


The baseball's kinetic energy is greater than zero at that instant.


✅ At that moment, all the baseball's kinetic energy has been converted to potential energy. (correct answer)
Physics
1 answer:
Akimi4 [234]2 years ago
3 0

Answer: At that moment, all the baseball's kinetic energy has been converted to potential energy.

Explanation: I took the test

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A decrease in mass will decrease an objects weight because 
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• What are common questions, concerns, practices, and experiences across various world religions? Include indigenous religions i
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<u>Answer:</u>

<em>They are a lot of religions and faiths across the globe. </em>

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Some of them are:

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5 0
3 years ago
A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string
alexdok [17]

Answer:

v_{max}=8.2226m/s

Explanation:

The problem is solved using the law of conservation of energy,

So

mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}

v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}

v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}

v_{max}=8.2226m/s

8 0
3 years ago
A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)<br>​
Vadim26 [7]

Answer:

\huge\boxed{\sf f=0.55 \ Hz}

Explanation:

<u>Given Data:</u>

Length = l = 820 mm = 0.82 m

Acceleration due to gravity = g = 9.8 ms⁻²

<u>Required:</u>

Frequency = f = ?

<u>Formula:</u>

\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }

<u>Solution:</u>

\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}

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a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we n
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Answer:

we use the formula,

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h = (89 {}^{2}  - 76 {}^{2} ) \div 20

h= 107 m

5 0
3 years ago
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