Answer:
vf = 11.2 m/s
Explanation:
m = 10 Kg
F = 2*10² N
x = 4.00 m
μ = 0.44
vi = 0 m/s
vf = ?
We can apply Newton's 2nd Law
∑ Fx = m*a (→)
F - Ffriction = m*a ⇒ F - (μ*N) = F - (μ*m*g) = m*a ⇒ a = (F - μ*m*g)/m
⇒ a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²
then , we use the equation
vf² = vi² + 2*a*x ⇒ vf = √(vi² + 2*a*x)
⇒ vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s
You must times the area by the volume, look at it as if the area is just one of 23 layers that makes up the volume.
1960x23=45080
so no it cannot be carried as it is 5080cm^3 over the limit
Answer:
10 watts
Explanation:
first calculate work.
Work =force×distance cos thita
10Kg×0.50M cos 0= 5joules
Therefore, Power=Work÷ Time
Therefore, 5joules÷0.50s=10 watts.
This is a concave mirror you're talking about, so all of the points are going to converge to a single focal point. Therefore the answer would be that it bounces back toward a single spot
Once again, you'd need to know that there are 60 seconds in a minute, and 60 minutes in an hour :)
I'd say converting the minimum wage into cents rather than dollars would make this problem a lot easier. $8.25 = 825 ¢.
So if this person is earning 825 ¢ in an hour, we should divide 825 by 60 to find out how much they're making in a minute:
825 ÷ 60 = 13.75 ¢
Now, we just need to divide by 60 again to work out how much that is in seconds:
13.75 ÷ 60 = 0.229 ¢
So to answer your question, this person would make 0.229 ¢ a second (¢/s) on the job with minimum wage. Converting this value to dollars wouldn't be viable (as it'd just be $0.00, so it's best to leave the answer in cents!)
