The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
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i think the question is not correct write it again or attach the pic ic
Answer:
<h3>#1</h3>
<u>The system of equations:</u>
- 2x + 7y = -11
- 3x + 5y = -22
Solve by elimination.
<u>Triple the first equation, double the second one, subtract the second from the first and solve for y:</u>
- 3(2x + 7y) - 2(3x + 5y) = 3(-11) - 2(-22)
- 6x + 21y - 6x - 10y = -33 + 44
- 11y = 11
- y = 1
<u>Find x:</u>
- 2x + 7*1 = -11
- 2x = -11 - 7
- 2x = -18
- x = -9
<u>The solution is:</u>
<h3>#2</h3>
<u>Simplifying in steps:</u>
- 8u - 29 > -3(3 - 4u)
- 8u - 29 > - 9 + 12u
- 12u - 8u < -29 + 9
- 4u < -20
- u < -5