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OlgaM077 [116]
3 years ago
13

After a wire and filament have been connected, the second requirement for the conduction of electricity is a(n) _____. conductiv

e path energy source light bulb conductor
Chemistry
2 answers:
Fynjy0 [20]3 years ago
7 0

Answer:

ENERGY SOURCE

Explanation:

JUST TOOK QUIZ

Mrac [35]3 years ago
3 0

energy source

Explanation:

After wire and filament have been connected, for the conduction of electricity, an energy source is required.

In the energy source, electrical energy is produced.

  • The energy source can be a simple electrochemical cell.
  • It can be a generator.
  • It can also be current from the national grid.
  • The energy source produces current which is carried in wire and it powers the filament

Learn more:

Metals as conductors brainly.com/question/2474874

#learnwithBrainly

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How many ozone particles are needed to form 24 particles of oxygen gas?
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6 0
3 years ago
CH3 + HCl &lt;=&gt; CH3Cl + H2O
dmitriy555 [2]

Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

4 0
3 years ago
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