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LenKa [72]
2 years ago
9

Can someone help me really please

Mathematics
2 answers:
adell [148]2 years ago
6 0

Answer:

C

Step-by-step explanation:

NARA [144]2 years ago
4 0

Answer:

b

Step-by-step explanation:

3/3 = 1

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3x-1/5=x+1/3 solve for x
Maru [420]

Answer:

x = 2

Step-by-step explanation:

First, you cross multiply then that will give you

9x - 3 = 5x + 5

collect like terms

9x - 5x = +5 + 3

= 4x = 8

Divide both sides by the coefficient of x that's 4

= 2

6 0
2 years ago
Hiiii help please ahh
Brilliant_brown [7]

Answer:

Question 1 Answer : x^2 - 2y^2

Question 2 Answer: x^2\pi - 36\pi

7 0
2 years ago
Read 2 more answers
What’s the correct answer for this question?
xxMikexx [17]

Answer:

12.22

Step-by-step explanation:

To find HI, you have to use tangent. tanx=\frac{opposite}{adjacent}

tan(42°)=\frac{11}{HI} , then you multiply HI to both sides of equation and divide tan(42).

To get <em>HI</em>=\frac{11}{tan(42)}

Which makes HI equal 12.2167

5 0
2 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
Use the discriminant to describe the roots of each equation. then select the best description. x^2 - 4x + 4 = 0
Vaselesa [24]
B is the answer to the question
3 0
3 years ago
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