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allsm [11]
3 years ago
6

Please help. Ella has 5 pink bows, 1 blue bow, and 4 purple bows in a box, she will randomly choose 1 bow from the box. What is

the probability Ella will choose a purple bow? Please explain.
Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:

4/10 chance. Or 2/5. 40% chance.

Step-by-step explanation:

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Which statement correctly finds the interquartile range for the set of data represented by the box plot?
gizmo_the_mogwai [7]

Answer:

<em>B. 11 - 6 = 5</em>

Step-by-step explanation:

Median: 9.5

Lower Quartile: 6

Upper Quartile: 11

Interquartile Range: upper quartile - lower quartile = answer

6 0
3 years ago
Help - sorry it’s blurry I couldn’t fix it
Natali5045456 [20]
When we choose to do cosine we do adjacent/hypotenuse so it would be...

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4 0
3 years ago
The mean price for used cars is $10,550. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car
Evgen [1.6K]

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8 0
2 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
What’s the answer I need help!!
Kruka [31]

Answer:

150

Step-by-step explanation:

add three x plus 30 get 30 then add 6y plus 120 and get 120 add them and get 150

8 0
3 years ago
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