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3 years ago

A football team won 75% of 120 games in a season. How many games is that?

Mathematics

2 answers:

Luba_88 [7]3 years ago

8 0

Answer:

90 games

Step-by-step explanation:

Of the 120 games the football team played, they won 75% of them.

Remember that in mathematics, "of" almost always means to multiply. Here, that means we must multiply 75% by 120:

75% * 120

Remember also that % just means divided by 100, so 75% = 75 / 100. So:

75% * 120 = (75/100) * 120 = 9000/100 = 90 games

Bess [88]3 years ago

7 0

Answer: 90 games
Step by step explanation:

50% of 120 is half of it so that would be 60
10% of 120 is just 12
5% is 6
12x7=70% which is 84
Add 5% which is 6
84+6=90 so they played 90 games

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Simplify the expression. can anyone explain to me how to do this? please

WINSTONCH [101]

Answer:

The answer is the last one (32x^7y^15)

You can bring x to the second power (x^2) because (x) is basically x^1. This is a basic exponent rule. (x^m)^n = x^m times n.

Then you can apply this rule to (2xy^3)^5. First you bring two to the fifth power and get 32. Then you bring x^5 according to the rule. Then you bring y^15, also because of the rule.

Now you have:

x^2 times 32x^5y^15

Now you just multiply the like terms together (x^2 and x^5)

When you multiply two exponents with the same base, you add the exponents together: a^n times a^m = a^n+m.

So you end up with 32x^7y^15

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3 years ago

Read 2 more answers

A store pays $56 for a GPS navigation system. The markup is 25%.Find the selling price.

Phantasy [73]

$70

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3 years ago

Find f(-5) f(x) -4x + 3

Fiesta28 [93]

Answer:

if f(x)= -4x+3

f(-5)= 23

Step-by-step explanation:

first you substitute x for -5

f(-5)= -4(-5)+3

then you multiply

-4(-5)

f(-5)=20+3

you get the positive 20 because negative times negative equals positive

then you just add the rest (20+3) which will give you your answer

f(-5)= 23

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3 years ago

Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,

Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j} = {(1,0), (0,1)}

is a base in $\mathbb{R}^2$

and F is linear, then

{F(1,0), F(0,1)}

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

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3 years ago

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Shkiper50 [21]

3a squared +4a-7 squared is a 2 btw

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