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gladu [14]
2 years ago
15

What is the percentage yield if 125.4g C3H8 are collected from a reaction that should produce 157.4g C3h8?

Chemistry
1 answer:
cestrela7 [59]2 years ago
3 0

The percentage yield : 79.67%

The closest answer is option B.

<h3>Further explanation</h3>

Given

125.4 g C3H8

157.4 g C3H8

Required

The percentage yield

Solution

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

% yield = (actual yield : theoretical yield) x 100%

Input the value :

% yield = (125.4 : 157.4) x 100%

% yield = 79.67

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A 2.5 L container holds a sample of hydrogen gas at 291 K and 180 kPa.
netineya [11]

Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

\frac{P}{T} =k

When an ideal gas goes from a state 1 to a state 2, it is true:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 180 kPa
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Replacing:

\frac{180 kPa}{291 K} =\frac{350 kPa}{T2}

Solving:

T2=350 kPa*\frac{291 K}{180 kPa}

T2= 565.83 K

<u><em>The new temperature will be 565.83 K.</em></u>

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