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katen-ka-za [31]
3 years ago
13

In the following equation,

Chemistry
1 answer:
Nina [5.8K]3 years ago
3 0
It is C It is C It is C
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If 0.0369 mol CaCl2 is dissolved in water to make a 0.340 M solution, what is the volume of the solution
lesya692 [45]

Answer:

The correct answer is 0.11 L

Explanation:

From the problem, we have the following data:

moles CaCl₂= 0.039 mol

molarity = 0.340 M = 0.340 mol CaCl₂/L

According to this, the solution has 0.340 mol of CaCl₂ in 1 L. If the total number of moles is 0.0369, we can find the volume as follows:

V= moles/molarity = 0.0369 mol x 1 L/0.340 mol = 0.108 L ≅ 0.11 L

5 0
3 years ago
How many moles are present in 12.5 L of a 0.750M NaNO3 solution?
Step2247 [10]

Answer:

9.38 moles NaNO₃

Explanation:

Given the measurements provided, the best way to find moles is by using the molarity formula. The molarity formula is:

Molar concentration (M) = moles / volume (L)

Therefore, plug the provided values into the formula, then isolate to find moles.

Molar concentration (M) = moles / volume (L)

0.750 M = moles / 12.5 L

(0.750 M) x (12.5 L) = moles

9.38 = moles

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