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mestny [16]
3 years ago
9

PLEASE HELP ME

Mathematics
1 answer:
balandron [24]3 years ago
6 0

9514 1404 393

Answer:

  • (3y)(2x^2 -1x -8xy +4y)
  • (3y)(x -4y)(2x -1)

Step-by-step explanation:

<u>Part A</u>: All of the coefficients have a common factor of 3. All of the variable products have a common factor of y, so the greatest common factor of all terms is 3y. The expression can be written as ...

  (3y)(2x^2 -1x -8xy +4y)

__

<u>Part B</u>: The remaining factor can be factored pairwise:

  3y(x(2x -1) -4y(2x -1)) = 3y(x -4y)(2x -1)

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Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations  

(x-1)(x+3)=17+x ..... (1) and  

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

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This is the same equation as equation (1).  

Therefore, there will be the same solution set for equations (1) and (2).  (Answer)

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(x-1)(x+3)=17+x ..... (3) and  

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).  

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

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