4n=100 what is the value of n

In JKL and PQR, if JK PQ, KL QR, and K Q, then JKL must be congruent to PQR. True or false?

Levart [38]

I believe the answer is true.

4 0

3 years ago

I need help with my math, and only the correct answers please and if you don't mind can you teach me how to do it? It might seem

sweet-ann [11.9K]

Answer:

if you need help I'm here

Step-by-step explanation:

okay so these pictures aren't very clear and if you want I'll give you my socials to help you!! it really depends on what grade you're in though!!

7 0

3 years ago

Read 2 more answers

Subtract. (6x + 5) - (x + 3) A. 5x + 2 B. 6x + 2 C! 6x + 8 D. 5x + 8

Natali [406]

Answer: 5x + 2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which one is the answer? Answer these two

kirill [66]

Answer

Expressions 4(x+5) and 5(x+4) are Equivalent

Expressions 5(2m+2) and 10m+10 are not equivalent

Step-by-step explanation:

Heres why,

4(x+5) and 5(x+4)

4 times x =4x, so multiply 4x by 5 which should give you 20.

and multiply 5 to x which would be 5x and multiply that to 4 which would be 20, they match up so they are Equivalent.

5(2m+2) and 10m+10

times 5 to 2m to get 10m and times 10m by 2 to get 20.

10m+10 = 1 which they are not equivalent

8 0

3 years ago

Read 2 more answers

Two thirds of a number decreased by six is two. what is the number?

Kisachek [45]

Answer: The number is: " 12 ".

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Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;
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Method 1)

Add "6" to EACH SIDE of the equation;
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→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:

→ $\frac{2}{3}$ x = 8 ;
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Multiply each side of the equation by " $\frac{3}{2}$ " ; to isolate "x" on one side of the equation ; and to solve for "x" ;
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→ $\frac{3}{2}$ * $\frac{2}{3}$ x = 8 * $\frac{3}{2}$ ;

→ x = 8 * $\frac{3}{2}$ ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;

= $\frac{8*3}{1*2}$ ;

= $\frac{24}{2}$ ;

= 12 .
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x = 12 .
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Method 2)
______________________________________________
$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;

Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:
→ $\frac{2}{3}$ x = 8 ;
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Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
 → 3 * $\frac{2}{3}$ x = 8 * 3 ;
→ $\frac{3}{1}$ * $\frac{2}{3}$ x = 8 * 3 ;
→ $\frac{3*2}{1*3}$ x = 8 * 3
→ $\frac{6}{3}$ x = 24 ;

→ 2x = 24 ;

→ Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" :

2x / 2 = 24 / 2 ;

x = 12 .
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Method 3).
__________________________________________________
$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:

→ $\frac{2}{3}$ x = 8 ;
______________________________________________
Now, divide each side of the equation by " $\frac{2}{3}$ " ;
to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{ $\frac{2}{3}$ x } / { $\frac{2}{3}$ } = 8 / { $\frac{2}{3}$ } ;

to get: x = 8 / { $\frac{2}{3}$ } ;

= 8 * ( $\frac{3}{2}$ ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;

= $\frac{8*3}{1*2}$ ;

= $\frac{24}{2}$ ;

= 12 ;
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x = 12 .
___________________________________________
NOTE: Variant: (in "Methods 2 & 3") :
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At the point where:
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= 8 * ( $\frac{3}{2}$ ) ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;
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We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
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{since: "8÷2 = 4" ; and since: "2÷2 =1" } ;
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and we can rewrite the expression:
__________________________________________
$\frac{8}{1}$ * $\frac{3}{2}$ ;
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as: $\frac{4}{1}$ * $\frac{3}{1}$ ;
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which equals:
__________________________________________
→ $\frac{4*3}{1*1}$ ;

= $\frac{12}{1}$ ;

= 12 .
__________________________________________
x = 12 .
__________________________________________
Answer: The number is: " 12 ".
__________________________________________

8 0

4 years ago