All categories

3 years ago

The graph shows a proportional relationship between the distance a car travels and the fuel it consumes.

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

2.5

Step-by-step explanation:

if you take 80 and 120 on the graph look at the middle you get 100 and in between 2 and 3 you get 2.5 so it would take 2.5 gallons of gas for 100 miles

You might be interested in

PLEASE HELP. Prove that the value of the expression: b (36^5−6^9)(38^9−38^8) is divisible by 30 and 37.

pishuonlain [190]

Answer:

Step-by-step explanation:

First factor the second binomial

38^9 - 38^8 = 38^9 (38 - 1 ) = 38^9(37)

So there's your 37. This whole expression is divisible by 37

Now do the first binomial

36^5 - (36^4)*6

36^4(36 - 6)

36^4(30) and there's your thirty.

That first term is going to cause a bit of trouble showing that 36^4 * 6 = 6^9

6(36^4) = 6(6^2)^4 = 6^1 * 6^8 = 6^9

So this factors into 30*(36^4)*37*38^9

3 0

3 years ago

Someone tell me the answer and how y’all day been

Aloiza [94]

Answer:

I believe it is e.

Step-by-step explanation:

2/5 equals 0.4, which is the same as 0.40

4 0

2 years ago

Read 2 more answers

five whole numbers are written in order. 4 6 x y 10. the mean and median of the five numbers are the same. work out the values o

Artemon [7]

Answer:

x= 7

y= 8

Step-by-step explanation:

3 0

2 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

What is the length of line segment AB, rounded to the nearest tenth?

labwork [276]

Answer:

did they give you options?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers