I guess you are asking to find the sum of the first 8 terms. If so, then:
Sum = a₁(1-rⁿ)/(1-r), where a₁ is the 1st term, r=common ratio and n=number of terms:
the 1st term a₁ =3
common ratio r = - 2 (since -6/3 = - 2, and 12/-6 = - 2, etc.)
Sum = 3[(1- (-2)⁸]/(1-2) = 3(1- 256)/(1/2)
Sum = -1530
Let , smallest integer is x.
So , other one is x + 1.
By , given conditions :

Since, the numbers are positive so, x = -2 is ignored.
Therefore, the numbers are 9 and 10.
Hence, this is the required solution.
Answer:
13,800
Step-by-step explanation:
Answer:
The determinant of J can be found using the formula ad - bc
where ![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
So we have 
Step-by-step explanation: