From the function given:
y=x^2-5
this can be written as:
y=x^2+0x-5
writing in vertex form we get:
y=(x-h)^2+k
where: (h,k) is the vertex
y=(x-0)^2-5
thus the vertex is at (0,-5)
the parent function is y=x^2, thus the graph of the parent function is First graph
Answer:
It does not converge
Step-by-step explanation:
Step-by-step explanation:
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They would both be on a different axis.
