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3 years ago

A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N

Physics

1 answer:

Alex777 [14]3 years ago

6 0

Answer:

485.62 N

Explanation:

To obtain the magnitude of unbalanced forces acting on the body;

Unbalanced Force = Horizontal Component of Applied Force - Frictional Force

Frictional Force = Horizontal Component of Applied Force - Unbalanced Force

f = frictional force = ?

F = Applied force = 593 N

m = mass of person = 49 kg

a = acceleration = 0.57 m/s²

θ = Angle with horizontal = 30°

Hence;

Horizontal Component of Applied Force = (593 N)(Cos 30°)

Unbalanced Force = (49 kg)(0.57 m/s²)

f = (593 N)(Cos 30°) - (49 kg)(0.57 m/s²)

f = 513.55 N - 27.93 N

f = 485.62 N

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Answer:

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4 years ago

A worker pushes a 1080 N crate with a horizontal force of 345 N a distance of 14 m. Assume the coefficient of kinetic frictin be

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Answer:

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Explanation:

Given that,

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