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2 years ago

ASAP!!!! PLZZZZZZ!!! ILL THANK U AND GIVE BRAINLY ANSWER!!!

Mathematics

1 answer:

AlexFokin [52]2 years ago

4 0

Answer:

Step-by-step explanation:

Volume = 1800 cm^3

The volume formula is V = L*w * h

The length = 12

The width = 10

The height = x

12*10*x = 1800

120 * x = 1800

x = 1800/120

x = 15

The rock is 15 cm high.

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Pia needs 2/3 yard of fabric to cover a bench. Which amount of fabric is greater than

Fudgin [204]

Answer:

5/6 and 7/9

Step-by-step explanation:

A and D are less than 2/3 so B and C is correct.

Hope this helps plz mark brainliest :D

6 0

3 years ago

If two fractions are between 0 and 1, can their product be more than 1? please explain. Thank You.

notka56 [123]

Answer:

B) always less than either of the original fractions

Step-by-step explanation:

We can easily Answer this by taking some values.

The question states that the two fractions, each have values between 0 and 1.

Let us say one of the fraction is 1/2 and the other fraction is 1/3 .

The product of the two fractions is 1/2 x 1/3 = 1/6 .

is lesser than both 1/2 and 1/3 .

So, the correct answer is that the product is always less than either of the original fractions.

6 0

3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

3 years ago

During second period, Janet completed a grammar worksheet.

Dmitry_Shevchenko [17]

Answer: 50%

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A line passes through the point (-6,7) and has a slope of -2 write an equation in point slope form for this line

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

(-6,7) & m = -2

point slope form of line : y - y₁ = m (x-x₁)

y - 7 = (-2) (x - [-6] )

y - 7 = (-2) (x + 6)

y - 7 = -2x - 2 * 6

y - 7 = -2x - 12

2x + y = -12 +7

2x + y = -5 0r y = -2x - 5

3 0

3 years ago