A firefighter is using a hose and the flow rate of the water leaving the hose. the speed of the water leaving the hose is mathematically given as
u = 9.947 m/s
<h3>What is the speed of the water leaving the hose?</h3>
Generally, the equation for Volume flow rate is mathematically given as
(V)= (A) * (u)
Where
A= area
v=velocity
Therefore
V = A*u
V=0.032 m3/s
A=πR2
A= π*0.013
u=V/A
u=0.032/π*0.0322
u = 60.27m/s
In conclusion, the speed of the water leaving the hose
u = 60.27m/s
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Answer:
sweeps out equal areas in equal times.
Explanation:
As we know that there is no torque due to Sun on the planets revolving about the sun
so we will have
now we have
now we also know that
so rate of change in area is given as
so we will have
since angular momentum and mass is constant here so
all planets sweeps out equal areas in equal times.
Answer:
Explanation:
Single-phase transformers can operate to either increasing or decreasing the voltage applied to the primary winding. When a transformer is used to “increase” the voltage on the secondary winding with respect to the primary, it is called a Step-up transformer
The answer is; 2.
To balance a chemical equation, the moles on one side of the equation has to be the same as that on the other side. This ensures that the law of conservation is observed because matter or energy can't be created or destroyed but can only be transformed from one form to another.
In this equation, putting 2 in front of NaCl ensures that there are 2 moles of Na and CL just as there are 2 moles of Na and CL in the reactants side.
Answer: 394 Hz
Explanation: this is a question under Doppler effect.
The mathematical equation that defines a Doppler effect is given below as
fo = {c+ vo/ c - vs} × f
Where fo = frequency observed =?
c = speed of sound = 345 m/s
vo = velocity of observer relative to source = 9.5m/s
vs = velocity of source relative to observer = - 9.5 m/s ( the negative sign is as a result of the fact that the observer and the source are moving in opposite direction to each other)
f = frequency of sound by source = 394 Hz.
By substituting the parameters, we have that
fo = {345 + 9.5/ 345 - (-9.5)} × 394
fo = (345 +9.5/ 345 + 9.5) × 394
fo = (354.5/354.5) × 394
fo = 1 × 394 = 394 Hz