Complete Question
The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s.
(a) What is its angular acceleration in revolutions per minute-squared
(b) How many revolutions does the engine make during this 20 s interval?
rev
Answer:
a
b
Explanation:
From the question we are told that
The initial angular speed is 
The angular speed after 
is 
The time for revolution considered is 
Generally the angular acceleration is mathematically represented as
=> 
=>
Generally the number of revolution made is is mathematically represented as
=> 
=>
T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r
where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,
Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r
Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.
</span>
True because all switches use contacts to start or stop the flow of electrons in a circuit
Answer:
The generator produces electrical energy at a rate of 1378125000 J per second.
Explanation:
volume of water falling each second is 1250 
height through which it falls, h is 150 m
mass of 1 of water is 1000 kg
⇒mass of 1250 of water, m = 1250×1000 = 1250000 kg
acceleration due to gravity, g = 9.8 
in falling through 150 m in each second, by Work-Energy Theorem:
Kinetic Energy(KE) gained by it = Potential Energy(PE) lost by it
⇒KE = mgh
= 1250000×9.8×150 J
= 1837500000 J
Electrical Energy = 
(KE)
= ×1837500000
= <u>1378125000 J per second</u>
The grandfather clock will now run slow (Option A).
<h3>What is Time Period of an oscillation?</h3>
- The time period of an oscillation refers to the time taken by an object to complete one oscillation.
- It is the inverse of frequency of oscillation; denoted by "T".
Now,
, where L is the length and g is the gravitational constant, is the formula for a pendulum's period. - The period will increase as one climbs a very tall mountain because g will slightly decrease.
- Due to this and the previous issue, the clock runs slowly and it seems that one second is longer than it actually is.
Hence, the grandfather clock will now run slow (Option A).
To learn more about the time period of an oscillation, refer to the link: brainly.com/question/26449711
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