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dlinn [17]
2 years ago
7

A car was struck broadside, injuring the driver. you would expect that during the collision, the driver's:_________

Physics
1 answer:
il63 [147K]2 years ago
4 0

The driver's Body was pushed laterally while the head remained still.

When two objects collide side-by-side (broadside), the head tends to stay static while the body is forced laterally, injuring the neck. The motorist would presumably be protected by a side-curtain airbag rather than hurt.

<h3>A Broadside Collision: What Is It? </h3>

A broadside collision happens when the front of one car bangs into the side of another, usually at a high rate of speed. Although catastrophic injuries can occur in any automobile accident on the road, broadside collisions are especially dangerous.

<h3>Where is the most likely location for broadside collisions?</h3>

The majority of broadside collisions happen at or near junctions. This is due to the fact that crossroads design makes it easy for a broadside collision to occur, especially when motorists are not paying attention. The likelihood of a broadside collision increases when several vehicles cross paths at an intersection.

learn more about collision here

<u>brainly.com/question/24915434</u>

#SPJ4

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Answer:

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Explanation:

Let m is the mass of the object that is suspended vertically from a support. The potential energy stored in the spring is given by :

E_s=\dfrac{1}{2}kx^2

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x is the distance to the lowest point form the initial position.

When the object reaches the highest point, the stored potential energy stored in the spring gets converted to the potential energy.

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Equating these two energies,

\dfrac{1}{2}kx^2=mgx

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The expression for the oscillation frequency is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

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f=\dfrac{1}{2\pi}\sqrt{\dfrac{2\times 9.8}{0.18}}

f = 1.66 Hz

So, the oscillation frequency of the spring is 1.66 Hz. Hence, this is the required solution.

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