The initial velocity of a 4.0kg box is 11m/s due west. After the box slides 4.0m horizontally its speed is 1.5 m/s. Determine th e magnitude and the direction of the non conservative force acting on the box as it slides.
1 answer:
Answer:
The magnitude and direction of the non conservative force acting on the box is <F= 59.36 N - DUE EAST DIRECTION>.
Explanation:
m= 4 kg
Vi= 11 m/s
Vf= 1.5 m/s
d= 4m
d= Vi * t - a * t²/2
clearing a:
a= 2*(Vi * t - d)/ t²
Vf= Vi - a * t
replacing "a" and clearing t:
t= 2d/(Vf+Vi)
t= 0.64 s
found now the value of a:
a= Vi - Vf / t
a= 14.84 m/s ²
F= m * a
F= 59.36 N
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Kinetic energy is the energy associated with the motion of an object. It's a scalar quantity, there is no direction associated with KE and it has no components.
.
Therefore Kinetic energy is 817.96J.
More force is needed for more mass. Therefore, if the mass is greater and the force is not enough then the object will less likely accelerate
. Therefore Kinetic energy is 817.96J.