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fomenos
3 years ago
9

Find the sum of 5x3 3x²+5 and -2x²+6x²5

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

5×3=15

15+5=20

3x^2-2x^2=x^2

6x^2×5=30x^2

20+x^2+30x^2=20+31x^2

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Express y=3x+2 in general form
katrin [286]

General form of a linear equation is ax+by+c=0 where a,b, and c are three real numbers.

So, we can shift all the terms in one side of the equation. Hence, first step is to remove y from the left side. So, subtract y from each sides.

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4 0
3 years ago
How to turn this equation: <br> y= -1.02(x-3)^2+9.25<br> into factored form
MatroZZZ [7]

Answer:

y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})

Step-by-step explanation:

You first equate it to zero to get:

-1.02(x-3)^2+9.25=0

Then solve using square root method

-1.02(x-3)^2=-9.25

(x-3)^2=\frac{-9.25}{-1.02}

(x-3)^2=\frac{925}{102}

x=3\pm\sqrt{\frac{925}{102}}

Or

x=3\pm{\frac{5\sqrt{3774}}{102}}

x={\frac{306\pm5\sqrt{3774}}{102}}

Now work it backwards

102x-(306\pm5\sqrt{3774})=0

(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})=0

Hence the factored form is:

y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})

8 0
3 years ago
Hannah has a part-time job making holiday wreaths. This week, she made x medium wreaths, twice as many large wreaths as medium w
Lilit [14]

Answer:

Total number of wreaths = 3.5 wreaths

Step-by-step explanation:

Given:

Number of medium wreaths = x

Number of larger wreaths = 2[Number of medium wreaths]

Number of small wreaths = [1/2][Number of medium wreaths]

Find:

Total number of wreaths

Computation:

Total number of wreaths = Number of medium wreaths + Number of large wreaths + Number of small wreaths

Total number of wreaths = Number of medium wreaths + 2[Number of medium wreaths] + [1/2][Number of medium wreaths]

Total number of wreaths = x + 2x + 0.5x

Total number of wreaths = 3.5 wreaths

3 0
3 years ago
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