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fomenos
3 years ago
9

Find the sum of 5x3 3x²+5 and -2x²+6x²5

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

5×3=15

15+5=20

3x^2-2x^2=x^2

6x^2×5=30x^2

20+x^2+30x^2=20+31x^2

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Given the figure what is the value of x show your work
grandymaker [24]

51 + 3x+5 = 107

Simplify the left side:

3x + 56 = 107

Subtract 56 from both sides:

3x = 51

Divide both sides by 3:

x = 51 / 3

x = 17

Angle F and the outside angle of 107, need to equal 180 degrees.

F - 180 - 107 = 73 degrees.

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3 years ago
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SCORPION-xisa [38]

53 minutes

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3 years ago
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Factor completely: 12a^2b–18ab^2–30ab^3
Goryan [66]

Answer:

6ab(2a-3b-5b²)

Step-by-step explanation:

6(2a²b-3ab²-5ab³)

6a(2ab-3b²-5b³)

6ab(2a-3b-5b²)

7 0
3 years ago
What is the perimeter of triangle ABC ?
blagie [28]

Answer:

9+\sqrt{41}

Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where the variables are the respective points of B and C,

B (4,5) & C(-1,1)

So x_1 =4, y_1=5, x_2=-1, y_2=1

Plugging into the formula we get:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}

Summing it all (perimeter is sum of 3 sides):

Distance = 4+5+\sqrt{41}\\ =9+\sqrt{41}

3rd answer choice is right.

3 0
3 years ago
Find the midpoint of the line segment whose endpoints are (2.6,5.1) and (3,4.7).
svp [43]

Answer:

Mid point is: (2.8;4.9)

Step-by-step explanation:

To find midpoint of a line segment we can use the general equation:

Mid=\frac{x_1+x_2}{2} ;\frac{y_1+y_2}{2}

Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

Mid=\frac{2.6+3}{2} ;\frac{5.1+4.7}{2}

<h3>Mid point is: (2.8;4.9)</h3>

7 0
3 years ago
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