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Vladimir79 [104]
3 years ago
11

Plss helpPPPPPPPPPPPPPPPPPppp

Mathematics
2 answers:
Delicious77 [7]3 years ago
6 0

Answer:

5

Step-by-step explanation:

22.50/4.5 is 5

You can check this by doing 5x4.5=22.50

Hope this helps

kogti [31]3 years ago
4 0

Answer:

5 dollars

Step-by-step explanation:

divide money earned by hours of work

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Vinil7 [7]

Hello, please consider the following.

We know the following, right ?

(\forall a, b \in \mathbb{R}) \left( sin(a+b)=sin(a)sin(b)+cos(a)cos(b) \right)

So, here, it gives.

Asin(\omega t+\phi)=Asin(\phi){\sf \bf sin(\omega t)}+Acos(\phi){\sf \bf cos(\omega t)}\\\\=c_2{\sf \bf sin(\omega t)}+c_1{\sf \bf cos(\omega t)}\\\\\text{ *** where }c_2=Asin(\phi) \text{ and } c_1=Acos(\phi) \text{ ***}

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4 years ago
a storage drum in the shape of a cylinder is 3 feet tall and has a diameter of 4 feet. what is the total surface area of the sto
nlexa [21]

Answer:

SA=62.8\ ft^2

Step-by-step explanation:

we know that

The surface area of a cylinder is equal to

SA=2\pi r^{2}+2\pi rh

we have

h=3\ ft

r=4/2=2\ ft ----> the radius is half the diameter

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\pi =3.14

substitute

SA=2(3.14)(2)^{2}+2(3.14)(2)(3)

SA=62.8\ ft^2

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6 to the power of three is 216.
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4 years ago
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the figure below is a square . Find the length of side x in simplest radical form with a rational denominator.
wel

Answer:

\sqrt{14}

Step-by-step explanation:

In any square with side length s, the diagonal of the square is equal to s\sqrt{2}. Since the side length of this square is \sqrt{7}, the diagonal is equal to \sqrt{7}\cdot \sqrt{2}=\boxed{\sqrt{14}}.

Alternatively, you can form two 45-45-90 triangles with the diagonal of the square. The diagonal acts as the hypotenuse for the both these triangles, and the legs of both triangles are equal to the side length of the square. To find the length of the diagonal, use the Pythagorean Theorem, which states a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

In this question, both legs are equal to \sqrt{7}, and we're solving for the diagonal, which is the hypotenuse in this case:

\sqrt{7}^2+\sqrt{7}^2=c^2,\\c^2=14,\\c=\boxed{\sqrt{14}}

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