The answer is Absorption.
A = 1.15m/s2, Vf = 80.0km/h --> we need it in m/s, so:
Vf = 80km/h × 1000m/1km × 1h/3600s
= 22.22m/s
Top speed = Vf, initial speed = Vi
time (t) = V(Vf-Vi) ÷ a
t = (22.22-0)m/s ÷ 1.15m/s2
t = 22.22m/s × s2/1.15m
= 19.32 seconds
Answer:
ΔH = 249 kJ/mol
Explanation:
The balanced reaction is:
2H₂O(g) → 2H₂(g) + O₂(g) (1)
To calculate the energy change to obtain one mole of H₂(g) from one mole of H₂O(g), the coefficients of the reaction (1) must be halved:
H₂O(g) → H₂(g) + 1/2O₂(g) (2)
The enthalpy of the reaction (2) is given by:
<em>Where 
: is the bond enthalpy of reactants and 
: is the bond enthalpy of products.</em>
<u>For the reactants we have the next bond energies:</u>
2 x (H-O) = 2 x (467)
<u>And the bond energies for the products are:</u>
H-H + (1/2) (O=O) = 436 + (1/2)(498)
So, the enthalpy of the reaction (2) is:
I hope it helps you!
Answer:
(a)Work done and ΔE are negative
(b)Work done and ΔE are negative
(c)Work done and ΔE are positive
Explanation:
(a) When the two balls collide, the first billiard ball transfers its kinetic energy to the second ball which consequently starts rolling as the system ball comes to rest. Therefore, the decrease in internal energy takes places for both the system and energy transfer. Conclusively, Work done and ΔE are negative
(b) The drop of a book in this case system from a height transfers the potential energy to kinetic energy. Therefore, both the work is done by system on the floor and internal energy of the system decreases. In conclusion, Work done and ΔE are negative
(c) A father pushing daughter on swing which is system implies that he applied some force therefore transferring energy from the source to system. This means the internal energy of the system increases and so both the work done and ΔE are positive
