Explanation:
In the figure attached:
A boy travels AB distance of 100 m, with speed of 1.00 m/s
AB = 100 m
After reaching at point B he stops there at for 30 seconds.
After , 30 seconds he he comes back to his initial position that is A with steady speed of 1.00 m/s.
Distance covered from B to A= 100 m
Time taken by him during coming back=
After returning to to point A he turns left and moves towards point C with speed of 1.5 m/s for 2 minutes.
Distance of AC = ?
AC = 180 m
The total time of his round trip is:T
The total distance: D
D = AB + BA (returning) + AC=100 m + 100 m + 180 m = 380 m[/tex]
The total displacement of boy:
Displacement is the shortest distance between the initial point and final point.
He first walked to point B from A and then came back to A . And after that walking to point C from A.So, the final displacement (d) is from A to C.
d = AC = 180 m
The total displacement of boy is 180 m.
The average speed of the boy is given by:
The average velocity of the boy is given by:
