All categories

3 years ago

How does a nuclear plant operate

2 answers:

7 0

Nuclear plants harness the process of nuclear fission. Heavy elements like Uranium naturally decay and produce extra energy through the process. These energies can be harnessed and used to heat water to form steam; this change powers electric generators. This process continues until the uranium is depleted, the uranium is replaced, and the process begins again.

slava [35]3 years ago

3 0

A process called fission

You might be interested in

If you burn 55.6 g of hydrogen and produce 497 g of water, how much oxygen reacted?

tester [92]

Answer:

441.28 g Oxygen

Explanation:

The combustion of hydrogen gives water as the product.
The equation for the reaction is;

2H₂(g) + O₂(g) → 2H₂O(l)

Mass of hydrogen = 55.6 g

Number of moles of hydrogen

Moles = Mass/Molar mass

= 55.6 g ÷ 2.016 g/mol

= 27.8 moles

The mole ratio of Hydrogen to Oxygen is 2:1

Therefore;

Number of moles of oxygen = 27.5794 moles ÷ 2

= 13.790 moles

Mass of oxygen gas will therefore be;

Mass = Number of moles × Molar mass

Molar mass of oxygen gas is 32 g/mol

Mass = 13.790 moles × 32 g/mol

<h3> = 441.28 g</h3><h3>Alternatively:</h3>

Mass of hydrogen + mass of oxygen = Mass of water

Therefore;

Mass of oxygen = Mass of water - mass of hydrogen

= 497 g - 55.6 g

6 0

3 years ago

Read 2 more answers

!!29 POINTS!! PLS HELP ASAP

ICE Princess25 [194]

Answer:

The person who just wanted points is annoying

Explanation:

WHY WOULD YOU DO THAT

8 0

3 years ago

Which has a greater volume, 10 grams of water or 10 grams of acetone?

WINSTONCH [101]

Density is defined as the ratio of mass to the volume.

Density = $\frac{Mass}{Volume}$ (1)

Mass of water = 10 grams

Mass of acetone = 10 grams

Density of water = 1 $\frac{g}{cm^{3}}$

Density of acetone = 0.7857 $\frac{g}{cm^{3}}$

Put the value of density of water and its mass in equation (1)

1 $\frac{g}{cm^{3}}$ = $\frac{10 g}{volume}$

Volume of water = 10 $cm^{3}$

Put the value of density of acetone and its mass in equation (1)

0.7857 $\frac{g}{cm^{3}}$ = $\frac{10 g}{volume}$

Volume of acetone = 12.72 $cm^{3}$

Thus, volume of acetone is more than volume of water because the density of acetone is lower.

6 0

3 years ago

Calculate the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remain

Reil [10]

The balanced chemical equation for the production of chromium metal from the reaction of chromium(ll) nitrate reacts with a strip of zinc is:

3 Zn + 2 Cr(NO₃)₃ → 2 Cr + 3 Zn(NO₃)₂

This is a redox reaction, which <u>is a chemical reaction in which one or more electrons are transferred between the reagents</u>, causing a change in their oxidation states. In the proposed reaction, Cr oxidation state goes from +3 to 0, becoming metallic chromium, while Zn goes from being Zn⁰ to Zn²⁺.

<u>The mass of chromium metal produced in the above reaction will be,</u>

425.0 mL x $\frac{1 L}{1000 mL}$ x $\frac{0.25 mol Cr(NO_{3})_{3} }{1 L}$ x $\frac{2 mol Cr }{2 mol Cr(NO_{3})_{3} }$ x $\frac{51.9961 g Cr}{1 mol Cr}$ = 5.52 g

So, the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remains in excess is 5.52 g of Cr.

6 0

3 years ago

Significant Digits and Scientific Notation Part 1: Determine the number of significant digits in each number and write out the s

MA_775_DIABLO [31]

Answer:

1. 6 significant digits. 2. 2 significant digits. 3. 8 significant digits. 4. 4 significant digits. 5. 8 significant digits. 6. 7 significant digits. 7. 2 significant digits.

Explanation:

All nonzero digits are significant. All zeros before nonzeros are insignificant. All zeros after nonzeros are insignificant unless they are made for precision of some data. So 405000 may have 3 or 6 significant figures. But usually all zero figures after significant digits are significant.

8 0

3 years ago