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lilavasa [31]
3 years ago
11

What is the molality of a solution made by dissolving 5.2 g of NaCl in 100 g of water?

Chemistry
1 answer:
stich3 [128]3 years ago
8 0

Answer:

The molality is 0,89

Explanation:

A molal solution indicates the moles of solute in 1 kg of solvent (1000 g). First, we calculate the weight of 1 mol of NaCl:

Weight NaCl= Weight Na + Weight Cl=23g + 35,5 g=58,5 g/mol

58,5 g----1 mol NaCl

5,2 g----x=(5,2 gx1 mol NaCl)/58,5 g=0,089 mol NaCl

100g water-----0,089 mol NaCl

1000g water----x=(1000g waterx0,089 mol NaCl)/100 g water

x=0,89 mol NaCl----> <em>0,89 m</em>

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What mass of carbon dioxide is produced from the complete combustion of 5.30x10-3 g of methane?
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Answer:

1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

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5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
                                      16.043 g            1 mole CH₄            1 mole

=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

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