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3 years ago

What is the molality of a solution made by dissolving 5.2 g of NaCl in 100 g of water?

Chemistry

1 answer:

stich3 [128]3 years ago

8 0

Answer:

The molality is 0,89

Explanation:

A molal solution indicates the moles of solute in 1 kg of solvent (1000 g). First, we calculate the weight of 1 mol of NaCl:

Weight NaCl= Weight Na + Weight Cl=23g + 35,5 g=58,5 g/mol

58,5 g----1 mol NaCl

5,2 g----x=(5,2 gx1 mol NaCl)/58,5 g=0,089 mol NaCl

100g water-----0,089 mol NaCl

1000g water----x=(1000g waterx0,089 mol NaCl)/100 g water

x=0,89 mol NaCl----> <em>0,89 m</em>

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<h3>Further explanation</h3>

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